如何取两个日期之间的差异，具体取决于出生日期[重复]

Question

我的代码：

        function test(val) {
            year = parseInt(val.slice(0,2)); // get year
            month = parseInt(val.slice(2,4)); // get month
            date = val.slice(4,6); // get date

            if (month > 40) { // For people born after 2000, 40 is added to the month. (it is specific for my case)
                year += 2000;
                month -= 40;
            } else {
                year += 1900;
            }

            date = new Date(year, month-1, date, 0, 0);
            date_now = new Date();

            var diff =(date_now.getTime() - date.getTime()) / 1000;
            diff /= (60 * 60 * 24);
            console.log(Math.abs(Math.round(diff/365.25)));
        }

示例 1：

如果我出生在

1993-year;
04-month(april); 
26-date

我会将930426 作为值传递给测试函数，结果将是正确的 27

但是在示例2中：

如果我出生在：

1993-year;
09-month(september); 
14-date;

我会将930914 作为值传递给测试函数，结果是 27，但这不正确，因为我的生日还没到，我还 26 岁。

我该如何解决这个问题？

Answer 1

因为26.9仍然被认为是26的年龄，所以你应该改用.floor

function test(val) {
  year = +val.slice(0, 2) // get year
  month = val.slice(2, 4) // get month
  date = val.slice(4, 6) // get date

  date = new Date(year, month - 1, date, 0, 0)
  date_now = new Date()

  var diff = (date_now.getTime() - date.getTime()) / 1000
  diff /= 60 * 60 * 24
  console.log(diff / 365.25)
  console.log("Age", Math.floor(diff / 365.25))
}

test("930426")
test("930914")