如何将一个包含多个单词的字符串拆分成一个包含一定数量单词的字符串的列表？

Question

我有一个包含多种语言字符的字符串：

'죄송합니다 how are you doing? My name is Yudhiesh and I am 아니 doing good 저기요'

我正在尝试根据字符串中的单词数将此单个字符串分块为字符串列表，如果块大小为7，即字符串中最多有 7 个单词，结果应该是这样的：

['죄송합니다 how are you doing? My name', 'is Yudhiesh and I am 아니 doing', 'good 저기요']

我目前的尝试是基于你如何分块一个不起作用的列表：

s = '죄송합니다 how are you doing? My name is Yudhiesh and I am 아니 doing good 저기요'
>>> parts = [str(s[i:i+7]) for i in range(0, len(s), 7)]
>>> parts
['죄송합니다 h', 'ow are ', 'you doi', 'ng? My ', 'name is', ' Yudhie', 'sh and ', 'I am 아니', ' doing ', 'good 저기', '요']

Answer 1

首先，您可以创建一个单词列表，然后创建块并加入它们。

这是你需要的函数：

def split_max_num(string, max_words):
    """
    >>> split_max_num('죄송합니다 how are you doing? My name is Yudhiesh and I am 아니 doing good 저기요', 7)
    ['죄송합니다 how are you doing? My name', 'is Yudhiesh and I am 아니 doing', 'good 저기요']
    """
    words = string.split()
    len_words = len(words)

    res = list()
    for index in range(0, len_words, max_words):
        res.append(' '.join(words[index:index+max_words]))
    return res

Answer 2

下面的呢？

def split_max(words, n): 
    words = words.split()
    words = [words[i:i + n] for i in range(0, len(words), n)]
    return [' '.join(l) for l in words]


split_max(data, 7)

Answer 3

你确定你没有设置s=['죄송합니다 how are you doing? My name', 'is 도와 주세요 and I am doing', 'good 저기요'] 在此示例中生成 parts 之前？

您可能希望使用"somestring".split(" ") 拆分原始字符串，即拆分空格以获取所有单词的列表，然后您可以像尝试那样使用索引来切分列表。

Answer 4

在字符串上使用.split() 并将其分块：

from typing import List

def chunk_list(lst: List[str], chunk_size: int) -> List[List[str]]: 
    return [
        lst[i:i + chunk_size] 
        for i in range(0, len(lst), chunk_size)
    ]
     

def chunk_string(string: str, chunk_size: int) -> List[str]:
    return chunk_list(string.split(), chunk_size)

Answer 5

您正在将列表转换为列表的字符串表示形式。

我认为你的意思是重新加入这些词

s = '죄송합니다 how are you doing? My name is Yudhiesh and I am 아니 doing good 저기요'
s = s.split()
print([" ".join(s[i:i+7]) for i in range(0, len(s), 7)])