使用python删除前三个字符[重复]

Question

我有一个我在 python 中读取的数据。在“标题”列中，很少有行具有我想要删除的“新”等额外字符。我试图找到正确的代码，但我找不到任何代码，当我尝试自己的代码时，我得到了错误。任何人都可以帮忙！！！提前致谢。 title data

if indeed['title'] == indeed.loc[indeed['title'].str.startswith('new')].copy():
    indeed['title'].str[3:]

错误

---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-34-486b16b22bea> in <module>
----> 1 if indeed['title'] == indeed.loc[indeed['title'].str.startswith('new')].copy():
      2     indeed['title'].str[3:]

~/opt/anaconda3/lib/python3.7/site-packages/pandas/core/generic.py in __nonzero__(self)
   1325     def __nonzero__(self):
   1326         raise ValueError(
-> 1327             f"The truth value of a {type(self).__name__} is ambiguous. "
   1328             "Use a.empty, a.bool(), a.item(), a.any() or a.all()."
   1329         )

ValueError: The truth value of a DataFrame is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

Answer 1

如果我理解正确，我会阅读该列并搜索前 3 个字符 =='new'，如果匹配，则返回字符串中不包含前 3 个字符的列，否则按原样返回该列。

import pandas as pd
import numpy as np

mydata = pd.DataFrame(['software developer','newgis developer','javascript developer','newhr partner'])
mydata.columns=['title']
mydata['newcol']=np.where(mydata['title'].str[:3]=='new', mydata['title'].str[3:], mydata['title'])

print(mydata)  
                  title                newcol
0    software developer    software developer
1      newgis developer         gis developer
2  javascript developer  javascript developer
3         newhr partner            hr partner