随着输入的变化更新静态输出[关闭]

Question

我希望随着输入的变化更新屏幕上的构造。构造将如下所示：

puts "    |    |    "
puts "    |    |    "
puts "----+----+----"
puts "make an input (1/2/3/4/5/6)"
selection = gets.chomp
#process selection, returns value, value to be updated in construct.

我将值的空间定义为 2x3 数组。例如，返回的值可以是 '2' 以存储在空间 [0][1]（第 1 行，第 2 列）中。输出应如下所示：

    |  2 |
    |    |    
----+----+----

这需要在不重新打印构造的情况下发生。当提示用户（在循环中）进行另一个选择时，应该再次更新结构而不重新打印。

Answer 1

我可以让你感兴趣吗，好先生，good 和 evil 之间的战斗？深受TTT 的启发：

require 'dispel'

class Lucky6
  BOARD = <<-BOARD.gsub /^\s+/, ''
    | X | X | X |
    | X | X | X |
    ----+---+----
  BOARD

  attr_reader :position

  def initialize
    @fields   = Array.new(6) { ' ' }
    @position = 0
  end

  def board
    index = -1
    BOARD.gsub(" X ") do
      index += 1
      field = @fields[index]
      @position == index ? "[#{field}]" : " #{field} "
    end
  end

  def set(position)
    @position = position.pred
    @fields[@position] = position
  end
end

def draw(l6)
  [l6.board, "1..6=Set r=Reset q=Quit"].join("\n")
end

Dispel::Screen.open do |screen|
  l6 = Lucky6.new
  screen.draw draw(l6)

  Dispel::Keyboard.output do |key|
    case key
    when ('1'..'6') then l6.set(key.to_i)
    when "r" then l6 = Lucky6.new
    when "q" then break
    end
    screen.draw draw(l6)
  end
end

Answer 2

使用technique of \r无法实现您的要求，但您可以使用如下所示的清屏技巧

matrix = [ ["", "", ""], ["", "", ""]]
pos_to_index = [[0, 0], [0, 1], [0, 2], [1,0], [1,1], [1,2]]

system("cls")

begin
    print "make an input (1/2/3/4/5/6)\n"
    selection = gets.chomp
    system("cls")

    if (selection.to_i <= pos_to_index.size)

        pos = pos_to_index[selection.to_i - 1]
        matrix[pos[0]][pos[1]] = selection

        matrix.each { |a| a.each { |i| print " #{i.empty? ? ' ' : i} |" }; puts }
        puts "---+---+----"
    end 

end while (not selection.empty?)

PS：system("cls") 适用于 Windows，如果它不适合您，请尝试 system("clear") 解释 here