无法将 T.Type 类型的值转换为 T

Question

我正在尝试使用AlamofireObjectMapper 发送请求的通用方法，其中输入为BasicMappable（通用类型），输出为响应

func sendRequest<T>(endPoint: String,
                    parameters: Parameters,
                    method: HTTPMethod,
                    mappingObject: T.Type) -> T where T : BaseMappable {
        var answer = T.self
        Alamofire.request(applicationBaseURL + endPoint,
                          method: method,
                          parameters: parameters,
                          headers: nil)
            .responseObject { ( response: DataResponse<T>) in
                let data = response.result.value
                answer = data as! T.Type
        }
        return answer as! T
    }

所以我在 VC 中这样使用这个方法：

let authResponse = requestHelper.sendRequest(endPoint: "/auth/users/create/",
                                             parameters: params,
                                             method: .post,
                                             mappingObject: AnswerClass.self)

而且它构建得很好。 但是当我尝试发送请求时，我遇到了崩溃和错误

Could not cast value of type 'Travel.AuthController.AnswerClass.Type' (0x110186bf8) to 'Travel.AuthController.AnswerClass' (0x10de153b0).
2019-04-15 18:42:28.811494+0300 Travel[9951:596186] Could not cast value of type 'Travel.AuthController.AnswerClass.Type' (0x110186bf8) to 'Travel.AuthController.AnswerClass' (0x10de153b0).

我已经用这个在 VC 中做过了

Alamofire.request(applicationBaseURL + "/auth/users/create/",
                                  method: .post,
                                  parameters: params,
                                  headers: nil)
   .responseObject { (response: DataResponse<AnswerClass>) in
                        let loginRespone = response.result.value
                        for error in loginRespone?.errors ?? [] {
                            print(error.detail)
                            print(error.source)
                            print(error.status)
                        }

而且效果很好

但我想让这个方法对整个项目通用

如何正确转换这些类型的值或有其他方法吗？

Answer 1

感谢@Kamran 的帮助！

我的最终解决方案是：

class RequestHelper {
    func sendRequest<T>(endPoint: String,
                        parameters: Parameters,
                        method: HTTPMethod,
                        mappingObject: T.Type,
                        completion: @escaping (_ response: T?, _ error: Error?) -> Void) where T : BaseMappable {
        Alamofire.request(applicationBaseURL + endPoint,
                          method: method,
                          parameters: parameters,
                          headers: nil)
            .responseObject { ( response: DataResponse<T>) in
                switch response.result {
                case .success(let value):
                    completion(value, nil)
                case .failure(let error):
                    completion(nil, error)
                }
        }
    }
}

Answer 2

你需要使用completionHandler来获取对象，

func sendRequest<T>(endPoint: String,
                    parameters: Parameters,
                    method: HTTPMethod,
                    mappingObject: T.Type,
                    completion: (T?, Error?) -> Void) {
    Alamofire.request(applicationBaseURL + endPoint,
                      method: method,
                      parameters: parameters,
                      headers: nil)
        .responseObject { ( response: DataResponse<T>) in
            switch response.result {
            case .success(let value):
                completion(value, nil)
            case .failure(let error):
                completion(nil, error)
            }

    }
}