Mysql从另一个表的字段替换字段[重复]答案

【问题标题】：Mysql replace field from another table's field [duplicate]Mysql从另一个表的字段替换字段[重复]
【发布时间】：2013-05-24 01:35:32
【问题描述】：

选择查询时，我需要用 Table2 的值替换 Table1 的字段值。

例如：

表1：

Org                  Permission
--------------------------------------
Company1             1,3,7
Company2             1,3,8

表2：

Permission          Permission
--------------------------------------
1                   Read
3                   Write
7                   Execute
8                   Delete

我需要这样的：

Org                  Permission
--------------------------------------
Company1             Read,Write,Execute
Company2             Read,Write,Delete

【问题讨论】：

了解数据库规范化。
使用 replace() phptooltip.blogspot.in/2013/05/replacestrfromstrtostr.html
-1 请不要一遍又一遍地输入同一个问题 (stackoverflow.com/questions/16710990/oracle-replace-function) - 相反，请尝试改进您现有的问题。

标签： mysql sql

【解决方案1】：

自从你的帖子在 Oracle 中被标记后，我一直在关注它：D

在 oracle 中，它以多种可能的方式寻找，但在 mysql 中，您必须借助程序来遵循它：

架构：

create table table1 (org varchar(50), permission_id varchar(50));
create table table2 (permission_id int, permission_name varchar(50));

insert into table1 values ('Company1','1,3,7'),('Company2','1,3,8');
insert into table2 values (1,'Read'),(3,'Write'),(7,'Execute'),(8,'Delete');

程序：

    DELIMITER $$

DROP PROCEDURE IF EXISTS `Update_Table_data`$$

CREATE PROCEDURE `Update_Table_data`()
BEGIN
    declare max_row int;
    declare p1 int;
    Set p1 = 0;
    SET max_row = (SELECT max(@i:=@i+1) AS row_num FROM table2 AS t,(SELECT @i:=0) AS foo);

    label1: LOOP
    set p1 = p1 + 1;
    IF p1 <= max_row THEN
        UPDATE Table1
        SET permission_id = 
        replace(permission_id, (select permission_id from 
                    (SELECT @i:=@i+1 AS row_num ,t.* FROM table2 AS t,(SELECT @i:=0) AS foo) a
                    where row_num = p1), 
            (select permission_name from 
            (SELECT @i:=@i+1 AS row_num ,t.* FROM table2 AS t,(SELECT @i:=0) AS foo) a
            where row_num = p1));       
        Iterate label1;
    END IF;    
        LEAVE label1;
    END LOOP label1;
    -- SET @x = p1;
    END$$

DELIMITER ;

然后打电话更新你的价值观：

call Update_Table_data;

希望对你有帮助:)

【讨论】：

【解决方案2】：

初始数据见SQLFiddle，这是结果数据SQLFiddle

UPDATE 
    organization
SET 
    permisson = (SELECT 
                   GROUP_CONCAT(VALUE) 
                 FROM 
                  ( SELECT 
                      org,
                      SUBSTRING_INDEX(permisson,',',1) AS `permisson`
                    FROM 
                      organization 

                    UNION 

                    SELECT
                      org,
                      SUBSTRING_INDEX(SUBSTRING_INDEX(permisson,',',2),',',-1) AS `permisson` 
                     FROM 
                    organization

                    UNION 

                    SELECT
                      org,
                      SUBSTRING_INDEX(permisson,',',-1) AS `permisson` 
                    FROM 
                      organization
                   ) AS t 

                   JOIN 

                   permission p 

                   WHERE 
                    p.p_id = t.permisson AND 
                    t.org = organization.org 
                   GROUP BY org
)

【讨论】：

【解决方案3】：

尝试使用 REPLACE 替换您的号码。只有在您使用单个数字值作为权限时它才能正常工作。

    SQL = " SELECT Org, REPLACE(REPLACE(REPLACE(REPLACE(Permission,"1","Read'"),"3","Write'"),"7","Execute'"),"8","Delete'") as Permission FROM myTable "

REPLACE()

【讨论】：

投反对票有什么理由吗？不起作用？