查找和替换除某些短语文本文件外的 ruby

Question

我很确定我弄错了。但我希望这个程序运行完“phone_numbers.txt”并替换除["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"] 之外的任何重复内容。这段代码的结果绝对没有。没有改变。有什么建议吗？

file_names = ['phone_numbers.txt']
    file_names.each do |file_name|
      words_to_exclude = ["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"]
      text = File.read(file_name)
      lines = text.split("\n")
      new_contents = lines.uniq.reject do |word|
        words_to_exclude.include? word
      end.join("\n")
      File.open(file_name, "w") { |file| file.puts new_contents }
    end

Answer 1

我不确定我是否理解正确，但是使用带有块的Array#uniq 应该可以解决问题：

require 'digest/sha1' # to generate uniqs

file_names = ['phone_numbers.txt']
words_to_exclude = ["Employee Marked Urgency as: low",
                    "Employee Marked Urgency as: high"]

file_names.each do |file_name|
  res = File.readlines(file_name).each_with_index.uniq do |s, idx|
    words_to_exclude.include?(s) ?
      Digest::SHA1.hexdigest(idx.to_s) : s
  end.join("\n")
  File.write(file_name, res)
end

这里发生了什么：如果我们遇到列表中的单词，我们会生成一个 uniq 足够的字符串以让其通过；否则我们使用原始字符串进行比较。