根据评论更新
我找到了一种方法:
1 - 对象动态样本:
dynamic dynamicStuff = new
{
Name = "John",
Surname = "Smith",
Obj = new { City = "New York", State = "NY" },// i add this to test object
Addresses = new[]
{
new { City = "New York", State = "NY"},
new { City = "Milano", State = "IT" }
}
};
2 - 序列化和反序列化以构建动态对象:
dynamic dynamicStuffDeSerialized = JsonConvert.DeserializeObject(JsonConvert.SerializeObject(dynamicStuff));
3 - 将dynamic 对象转换为JObject 并通过将JObject 转换为Dictionary 来构建(字符串,对象)的Dictionary:
Dictionary<string, object> keyValuePairs = ConvertJObject(JObject.FromObject(dynamicStuffDeSerialized));
private static Dictionary<string, object> ConvertJObject(JObject jObject)
{
Dictionary<string, object> keyValuePairs = new Dictionary<string, object>();
foreach (var property in jObject)
{
if (property.Value.Type == JTokenType.Array)
keyValuePairs.Add(property.Key, ConvertJArray(property.Value.Select(o=>(JObject)o)));
else if (property.Value.Type == JTokenType.Object)
keyValuePairs.Add(property.Key, ConvertJObject((JObject)property.Value));
else
keyValuePairs.Add(property.Key, property.Value.ToString());
}
return keyValuePairs;
}
private static List<Dictionary<string, object>> ConvertJArray(IEnumerable<JObject> jObjects)
{
return jObjects.Select(o => ConvertJObject(o)).ToList();
}
请注意,您可以使用ToObject 将JObject 转换为Dictionary,但它只是转换简单值而不是对象或数组,例如:
JObject jObject = JObject.FromObject(dynamicStuffDeSerialized);
Dictionary<string, object> dict = jObject.ToObject<Dictionary<string, object>>();
4 - 使用Hash.FromDictionary 而不是Hash.FromAnonymousObject:
Template templatedynamicStuff = Template.Parse("Hello {{Name}} {{Surname}} City in Object {{Obj.City}}. Number of Addresses: {{Addresses.size}} - {{Addresses[0].City}} - {{Addresses[1].City}}");
string result = templatedynamicStuff.Render(Hash.FromDictionary(keyValuePairs));
请注意,我通过添加 City in Object {{Obj.City}} 更改了 template
5 - 测试
Console.WriteLine(result);
6 - 结果:
Hello John Smith City in Object New York. Number of Addresses: 2 - New York - Milano
旧答案
根据 newtonsoft 文档,您可以使用 DeserializeAnonymousType 而不是 DeserializeObject 来反序列化匿名对象。但是DeserializeAnonymousType 需要 匿名 类型的definition 才能获得相同的对象。
如下代码:
var stuff1 = new
{
Name = "John",
Surname = "Smith"
};
var stuff1Serialized = JsonConvert.SerializeObject(stuff1);
var definition = new { Name = "", Surname = "" };
dynamic stuff1Deserialized = JsonConvert.DeserializeAnonymousType(stuff1Serialized, definition);
根据评论更新
您可以使用JObject 或ExpandoObject 获取属性names 和values,如以下代码:
dynamic stuff1 = new
{
Name = "John",
Surname = "Smith"
};
var stuff1Serialized = JsonConvert.SerializeObject(stuff1);
dynamic stuff1DeSerialized1 = JsonConvert.DeserializeObject(stuff1Serialized);
foreach (JProperty property in JObject.FromObject(stuff1DeSerialized1))
{
Console.WriteLine($"Key:{property.Name}, Value:{property.Value}");
}
ExpandoObject stuff1DeSerialized2 = JsonConvert.DeserializeObject<ExpandoObject>(stuff1Serialized, new ExpandoObjectConverter());
foreach(KeyValuePair<string, object> keyValue in stuff1DeSerialized2.ToList())
{
Console.WriteLine($"Key:{keyValue.Key}, Value:{keyValue.Value}");
}
希望能找到其他的解决方案与大家分享。