【发布时间】：2020-06-05 15:44:38
【问题描述】：
最近我开始学习使用 swift 开发 iOS 应用程序，所以我是新手。我想在 swift 中实现 rest api 调用并发现我们可以使用URLRequest 来实现这一点。所以我写了generic method来调用rest api的所有类型（如get, put, post），如下所示。
import Foundation
//import Alamofire
public typealias JSON = [String: Any]
public typealias HTTPHeaders = [String: String];
public enum RequestMethod: String {
case get = "GET"
case post = "POST"
case put = "PUT"
case delete = "DELETE"
}
public enum Result<Value> {
case success(Value)
case failure(Error)
}
public class apiClient{
private var base_url:String = "https://api.testserver.com/"
private func apiRequest(endPoint: String,
method: RequestMethod,
body: JSON? = nil,
token: String? = nil,
completionHandler: @escaping (Data?, URLResponse?, Error?) -> Void) {
let url = URL(string: (base_url.self + endPoint))!
var urlRequest = URLRequest(url: url)
urlRequest.httpMethod = method.rawValue
urlRequest.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
if let token = token {
urlRequest.setValue("bearer " + token, forHTTPHeaderField: "Authorization")
}
if let body = body {
urlRequest.httpBody = try? JSONSerialization.data(withJSONObject: body)
}
let session = URLSession(configuration: .default)
let task = session.dataTask(with: urlRequest) { data, response, error in
//NSLog(error)
completionHandler(data, response, error)
}
task.resume()
}
public func sendRequest<T: Decodable>(for: T.Type = T.self,
endPoint: String,
method: RequestMethod,
body: JSON? = nil,
token: String? = nil,
completion: @escaping (Result<T>) -> Void) {
return apiRequest(endPoint: endPoint, method: method, body:body, token: token) { data, response, error in
guard let data = data else {
return completion(.failure(error ?? NSError(domain: "SomeDomain", code: -1, userInfo: nil)))
}
do {
let decoder = JSONDecoder()
try completion(.success(decoder.decode(T.self, from: data)))
} catch let decodingError {
completion(.failure(decodingError))
}
}
}
}
这就是我从controller调用它的方法
public func getProfile(userId :Int, objToken:String) -> Void {
let objApi = apiClient()
objApi.sendRequest(for: ProfileDetails.self,
endPoint:"api/user/profile/\(userId)",
method: .get,
token: objToken,
completion:
{(userResult: Result<ProfileDetails>) -> Void in
switch userResult
{
case .success(let value):
if value.respCode == "01" {
print(value.profile)
do {
//... ddo some taks like store response in local db or else
} catch let error as NSError {
// handle error
print(error)
}
}
else {
//do some task
}
break
case .failure(let error):
print(error)
break
}
})
}
我正在解码以下模型中的服务器响应
class ProfileDetails : Response, Decodable {
var appUpdate : AppUpdate?
var profile : Profile?
enum CodingKeys: String, CodingKey {
case profile = "profile"
case respCode = "resp_code"
case respMsg = "resp_msg"
}
public required convenience init(from decoder: Decoder) throws {
self.init()
let values = try decoder.container(keyedBy: CodingKeys.self)
self.profile = try values.decodeIfPresent(Profile.self, forKey: .profile)
self.respCode = try values.decodeIfPresent(String.self, forKey: .respCode)!
self.respMsg = try values.decodeIfPresent(String.self, forKey: .respMsg)
}
}
此代码无法处理来自服务器的401, 404 等错误响应。所以我正在寻找的是将此api（URLRequest）请求转换为通用Alamofire请求，并使用401, 404等错误处理。我已经安装了Alamofire pod。是否有人开发了具有解码和错误处理的通用Alamofire 请求方法？
提前致谢:)
【问题讨论】：
-
我不知道为什么这个问题收到了反对票和一个关闭请求。我只是指定了我当前的代码和我正在寻找的内容。
-
我已经添加了一个答案加链接到 Github 项目，你可以下载和测试课程。如果您还需要其他任何东西，请告诉我。