【发布时间】:2015-05-28 21:45:59
【问题描述】:
我有以下查询,我想转换成 Mongo 那么我该怎么做
SELECT COUNT(*) AS count_all, DATE(created_at) AS date_created_at FROM “表”按日期分组(created_at)
还请解释一下,以便下次我可以自己做。
【问题讨论】:
标签: ruby-on-rails mongodb mongodb-query
我有以下查询,我想转换成 Mongo 那么我该怎么做
SELECT COUNT(*) AS count_all, DATE(created_at) AS date_created_at FROM “表”按日期分组(created_at)
还请解释一下,以便下次我可以自己做。
【问题讨论】:
标签: ruby-on-rails mongodb mongodb-query
您可以尝试以下方法。我希望这会对你有所帮助。
db."TABLE".group({
"key": {
"created_at": true
},
"initial": {
"count_all": 0
},
"reduce": function(obj, prev) {
if (true != null) if (true instanceof Array) prev.count_all += true.length;
else prev.count_all++;
}
});
【讨论】:
在 mongodb 中,您可以使用以下聚合管道:
db.collection.aggregate( [
{
$group: {
_id: "$created_at",
count_all: { $sum: 1 }
}
},
{
$project: {
_id: 0, date_created_at: "$_id", count_all: 1
}
}
])
然后可以将其转换为 ruby 语法:
project = {"$project" =>
{
"_id" => 0,
"date_created_at" => "$_id",
"count_all" => 1
}
}
group = { "$group" =>
{ "_id" => "$created_at", "count_all" => { "$sum" => 1 } }
}
Table.collection.aggregate([group,project])
更多示例,请参阅docs
【讨论】: