codeigniter 分页下拉选择过滤器

Question

我创建了一个网站，我在其中对项目下的项目进行了分组。当用户从提供的下拉菜单中选择一个项目并将其提交时，与该项目编号相关的项目将被检索并发送回控制器。

我的控制器

public function dwg_list()
{
    $data['proj_num'] = $this->model_proj->proj_num_all();
    $num_row = 1;
    if ($this->input->post('project_no') != '0')
    {
        $data['result'] = $this->model_issue->list_dwg($this->input->post('project_no'));

        if (count($data['result']) > 0)
        {
            $num_row = count($data['result']);
        } else $num_row = 1;
    }

    $this->load->library('pagination');

    $config['base_url'] = base_url() . '/index.php/dwg_issue/dwg_list/page';
    $config['total_rows'] = $num_row;
    $config['per_page'] = 2; 

    $this->pagination->initialize($config); 



    $data['main_content'] = 'dwg_list';
    $this->load->view('includes/template.php', $data);

}

我的观点

<h1>This page displays all the registered drawings</h1>
<br>

<div id="body">
<div class="row">
        <div class="form-group-sm"><lable class="col-sm-2 control-label">Project number:</lable>
    <?php
        $js = 'onchange="this.form.submit()" class="form-control" id="focusInput"';
        echo form_open('dwg_issue/dwg_list');
        echo "<div class=\"col-xs-2\">" . form_dropdown('project_no',$proj_num, $this->input->post('project_no'),$js)."</div>";
        echo form_error('project_no', '<div class="col-xs-4"><div class="alert alert-danger fade in"><a href="#" class="close" data-dismiss="alert" aria-label="close">&times;</a>','</div></div>');
    ?>
        </div>
        </div>
        <br>

<?php
echo "<noscript>".form_submit('submit','Submit')."</noscript>";
?>

        <table title="List of drawings" class="table table-hover" style="font-size: 14px">
            <caption><b>List of drawings</b></caption>
        <thead>
            <tr><th>Project number</th><th>Drawing number</th><th>Client drawing number</th>
                <th>Title</th><th>Size</th><th>Drawn by</th><th>Revision</th><th>Drawn Date</th></tr>
        </thead>    
        <tbody> &nbsp;
        <?php
            if(!empty($result))
            {
                foreach($result as $row)
                { 
                    echo "<tr>";
                    echo "<td>" . $row->project_no . "</td>";
                    echo "<td>" . $row->sws_dwg_no . "</td>";
                    echo "<td>" . $row->client_dwg_no . "</td>";
                    echo "<td>" . $row->dwg_title . "</td>";
                    echo "<td>" . $row->dwg_size . "</td>";
                    echo "<td>" . $row->dwg_by . "</td>";
                    echo "<td>" . $row->dwg_rev . "</td>";
                    echo "<td>" . date('Y/m/d', strtotime($row->dwg_date)) . "</td>"; 
                    echo "</tr>";
                }
            }

        ?>
        </tbody>
       </table>

       <?php echo $this->pagination->create_links(); ?>

</div>

我看到的问题是，当我单击下一个页码时，页面被刷新，下拉选择返回默认值，然后将其提交给控制器。控制器无法向模型提交任何内容以从数据库中检索。

那么我该如何克服这个问题。

Answer 1

如果我正确理解您的问题，我认为您可以使用URI Segments 传递您的项目编号，这样您就可以随时访问您选择的项目编号，而无需发布或使用发布方法。

public function dwg_list($porject_no){
    echo $porject_no;
    ......
}

示例： www.your-domain.com/controller/dwg_list/{project_no}

我希望这能给你一些想法。

这是一个链接，我认为可以提供帮助：

https://codeigniter.com/userguide2/general/controllers.html

Answer 2

也许将当前选择保存在表单处理程序“dwg_issue/dwg_list”中的会话变量中是有意义的

$this->session->set_userdata('selectedDropDownItem',$receivedDropDownItem);

每当您渲染视图时，您都会查看是否设置了会话变量“selectedDropDownItem”，然后在编写您的...时打印“selected”选项。

看看这个……

echo "<select>";
foreach ($selectOptions as $as){
            //check session if default option set....
            if (isset($this->session->userdata['selectedOption'])){
                $defOption = $this->session_userdata['selectedOption'];
            }else{
                  $defOption= "";
            }


            if (!strcmp($defOption,$as)){ // if the current option is equal to the session stored option...
                echo "<option value=\"".$as."\" selected=\"selected\">".$as."</option>";
            }else{
                echo "<option value=\"".$as."\">".$as."</option>";  
            }           
        }
echo "</select>";