如果查询包含 HAVING 语句，Laravel 分页不起作用

Question

Laravel having子句的分页查询问题，请看下面的查询

$data = DB::table('jobs as j')
    ->selectRaw('j.*, (case
        when (seeker_action = 'like' and employer_action = 'like') then 'match'
        when (seeker_action is null and employer_action = 'like') then 'employer-liking'
        when (seeker_action = 'like' and employer_action = 'delete') then 'rejected'
        else seeker_action end) as 'action'')
    ->join('profiles_jobs as p', 'p.job_id', '=', 'j.id')
    ->where('p.profile_id', '=', 2)
    ->whereRaw('(p.seeker_action is not null) or (p.seeker_action is null and p.employer_action = 'like')
        and j.deleted_at is null')
    ->having('action', 'employer-liking');

$data = $data->paginate(10);

我收到的错误如下：

未找到列：1054 '有子句'中的未知列 'action' (SQL: select count(*) as aggregate from jobs as j 内连接 profile_jobs as p on p.job_id = j.id 其中 p.profile_id = 2 和 (p.seeker_action 不为空) 或 (p.seeker_action 为空并且 p.employer_action = 'like')\nand j.deleted_at 是 null 有 action = 雇主喜欢）

我在 github 讨论上发布了这个并找到了解决方法，但我想知道是否有更好的解决方案。 Github laravel having issue discussion

Answer 1

你必须使用conditional WHERE clauses:

$data = DB::table('jobs as j')
    ->select('j.*')
    ->join('profiles_jobs as p', 'p.job_id', '=', 'j.id')
    ->where('p.profile_id', '=', 2)
    ->whereRaw("(p.seeker_action is not null) or (p.seeker_action is null and p.employer_action = 'like') and j.deleted_at is null")
    ->when($action === 'employer-liking', function($query) {
        $query->where('seeker_action', 'like')
            ->where('employer_action', 'like');
    })
    ->when($action === 'match', function($query) {
        $query->whereNull('seeker_action')
            ->where('employer_action', 'like');
    })
    ->when($action === 'rejected', function($query) {
        $query->where('seeker_action', 'like')
            ->where('employer_action', 'delete');
    });

$data = $data->paginate(10);

您还应该将whereRaw() 替换为where() and orWhere()。