为什么我的 django-filter 输入框没有出现？

Question

为什么我的 django-filter 输入框没有出现？我正在尝试用此过滤系统替换搜索栏，因此当他们在标题中搜索特定用户名时，他们将被定向到 account/filter_results.html 页面以显示过滤结果。但是，只出现了提交按钮，而没有出现输入框。请指教

filters.py

import django_filters

from account.models import Account


class UserNameFilter(django_filters.FilterSet):
    username = django_filters.CharFilter(lookup_expr='icontains')

    class Meta:
        model = Account
        fields = ['username']

views.py

def account_search_view(request, *args, **kwargs):
    context = {}
    account = Account.objects.all()
    context['account'] = account 
    username = UserNameFilter(request.GET, queryset=Account.objects.all())
    context['username'] = username
    return render(request, "account/filter_results.html", context)

urls.py

urlpatterns = [
    path('search/', account_search_view, name="search"),
]

header.html 页面

<form method="get">
{{ username.form }}
<input class="btn btn-success" type="submit"/>
</form>

filter_results.html 页面

    {% for obj in username.qs %}
        {{ obj.email }} - ${{ obj.price }}<br />
    {% endfor %}

models.py

class Account(AbstractBaseUser):
 email                  = models.EmailField(verbose_name="email", max_length=60, unique=True)
 username               = models.CharField(max_length=30, unique=True)

Answer 1

我收到了你的错误

    return render(request, "account/filter_results.html", context)

您正在将您的上下文传递给filter_results.html，并且您正在尝试访问header.html 如果你想在header.html 页面中访问你的表单而不是传递上下文也像这样

return render(request, "account/header.html", context)