【发布时间】:2015-07-08 15:21:30
【问题描述】:
我有一个分页,我想实现并将其限制为 5 个页码,
见下文:
例子:
PREVIOUS 1 2 3 4 5 NEXT
PREVIOUS 20 21 22 23 ... 39 NEXT
PREVIOUS 59 ... 81 82 83 84 NEXT
它们应该显示的只有五个页码。
我应该更改和修改代码的哪一部分?
我遇到了组合问题。
<?php
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous buttons
if ($page > 1)
$pagination.= "<a class='buttons' href=\"$targetpage?page=$prev\">previous</a>";
else
$pagination.= "<a class='disabled'><buttons disabled>previous</buttons></a>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a class='buttons' href=\"$targetpage?page=1\"> 1 </a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=2\"> 2 </a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next buttons
if ($page < $counter - 1)
$pagination.= "<a class='buttons' href=\"$targetpage?page=$next\">next</a>";
else
$pagination.= "<a class='buttons'>next</a>";
$pagination.= "</div>\n";
}
?>
我在跟踪显示页码的限制时遇到问题。
【问题讨论】:
-
注释后需要修改代码
//enough pages to hide some -
你能说得更具体点吗?我在几天内完成它,我无法弄清楚。雅罗曼达
-
“仅固定”?修复了什么?
-
哦,由于问题中没有javascript、jquery 或mysql,因此我删除了这些标签。
-
固定意味着..它的分页显示5页码只有当有很多记录要显示.. Cerbus
标签: php pagination