过滤数组以返回 JavaScript 中嵌套数组的匹配 ID [重复]答案

【问题标题】：Filter an array to return matching id's of a nested array in JavaScript [duplicate]过滤数组以返回 JavaScript 中嵌套数组的匹配 ID [重复]
【发布时间】：2022-01-29 03:30:28
【问题描述】：

例如，我有一个 location_id 为 1 的客户端对象。

还有一群员工。每个工作人员都包含一个嵌套的 location_ids 数组。我想过滤人员数组以将在其 located_at 数组中具有匹配 id 条目的所有人员返回到与客户端相同的 location_id。

staffMember obj 看起来是这样的：

contact_number: "4168455302"
email: "benshekhtman@hotmail.com"
first_name: "Ben"
id: 2
last_name: "Shekhtman"
located_at: [
  {id: 1, name: "Ben's Location"}
  {id: 2, name: 'My second location'}
  {id: 7, name: 'Medicare Clinic'}
]

这是我尝试的逻辑：

  const filterStaffByLocation = staff.filter((s) => {
    s.located_at.some((location) => location.id === client.location_id)
  })

当前 filterStaffByLocation 返回一个空的 []

更多详情： 如果人员数组如下所示：

[{
contact_number: "4168455302"
email: "benshekhtman@hotmail.com"
first_name: "Ben"
id: 2
last_name: "Shekhtman"
located_at: [
  {id: 1, name: "Ben's Location"}
  {id: 2, name: 'My second location'}
  {id: 7, name: 'Medicare Clinic'}
]
provider_id: 2
user_id: 2
user_type: "ADMIN"
},
{
contact_number: "9053700017"
email: "test@email.com"
first_name: "Test "
id: 3
last_name: "Team Member"
located_at: [
 {id: 3, name: 's'}
 {id: 7, name: 'Medicare Clinic'}
]
provider_id: 2
user_id: 7
user_type: "SUPPORT"
}]

针对 location_id 为 1 的客户端进行测试应该只返回第一个条目（id 为 2 的人员成员）

【问题讨论】：

标签： javascript arrays

【解决方案1】：

在你的队伍中

s.located_at.some((location) => location.id === client.location_id)

您忘记返回结果。

改成

return s.located_at.some((location) => location.id === client.location_id)

const client = {
    location_id:7
}

const staff = [{
contact_number: "4168455302",
email: "benshekhtman@hotmail.com",
first_name: "Ben",
id: 2,
last_name: "Shekhtman",
located_at: [
  {id: 1, name: "Ben's Location"},
  {id: 2, name: 'My second location'},
  {id: 7, name: 'Medicare Clinic'},
],
provider_id: 2,
user_id: 2,
user_type: "ADMIN",
},
{
contact_number: "9053700017",
email: "test@email.com",
first_name: "Test ",
id: 3,
last_name: "Team Member",
located_at: [
 {id: 3, name: 's'},
 {id: 7, name: 'Medicare Clinic'},
],
provider_id: 2,
user_id: 7,
user_type: "SUPPORT",
}]

  const filterStaffByLocation = staff.filter((s) => {
    return s.located_at.some((location) => location.id === client.location_id)
  })
  
  console.log(filterStaffByLocation)

.as-console-wrapper { max-height: 100% !important; top: 0; }

【讨论】：

【解决方案2】：

希望我明白你想要什么。但下面是如何做到这一点


/*
   Return all staff that have the location_id passed in
*/
const staffAtUserId = (staffArray,id)=>{
   // List to return 
   const retArr = []
   // Loop through all staff
   staffArray.forEach(staff=>{
       // Check if staff has that id in there location
       const hasLocationId = staff.located_at.some(obj=>obj.id===id)
       // If true at to return list
       if (hasLocationId){
           retArr.push(staff)
       }
   })
   return retArr
}

const staffArray = [{
    contact_number: "4168455302",
    email: "benshekhtman@hotmail.com",
    first_name: "Ben",
    id: 2,
    last_name: "Shekhtman",
    located_at: [
      {id: 1, name: "Ben's Location"},
      {id: 2, name: 'My second location'},
      {id: 7, name: 'Medicare Clinic'},
    ],
    provider_id: 2,
    user_id: 2,
    user_type: "ADMIN",
    },
    {
    contact_number: "9053700017",
    email: "test@email.com",
    first_name: "Test ",
    id: 3,
    last_name: "Team Member",
    located_at: [
     {id: 3, name: 's'},
     {id: 7, name: 'Medicare Clinic'}
    ],
    provider_id: 2,
    user_id: 7,
    user_type: "SUPPORT",
}]
console.log(staffAtUserId(staffArray,7))

【讨论】：