将字符串列表转换为 ISO 8601/RFC 3339 格式答案

【问题标题】：convert list of string to ISO 8601/RFC 3339 format将字符串列表转换为 ISO 8601/RFC 3339 格式
【发布时间】：2022-02-15 19:30:03
【问题描述】：

我有一个字符串列表start_date，其中包含 147 个不同的时间戳2022-02-05T22:58:59。我正在尝试将列表中的每个日期/元素转换为 ISO 8601/RFC 3339 格式YYYY-MM-DDTHH:mm:ssZ。

print(start_date)
['2022-02-05T22:58:59', '2022-01-27T22:58:59', '2022-01-27T22:58:59', '2022-01-25T22:58:59', '2022-01-22T22:58:59', '2022-01-21T22:58:59', '2022-01-15T22:58:59', '2022-01-11T22:58:59', '2022-01-09T22:58:59', '2021-12-29T22:58:59', '2021-12-15T22:58:59', '2021-11-26T22:58:59', '2021-11-24T22:58:59', '2021-11-05T22:58:59', '2021-10-24T22:58:59', '2021-10-14T22:58:59', '2021-10-09T22:58:59', '2021-09-29T22:58:59', '2021-09-18T22:58:59', '2021-09-16T22:58:59', '2021-09-12T22:58:59', '2021-08-29T22:58:59', '2021-08-28T22:58:59', '2021-08-27T22:58:59', '2021-08-22T22:58:59', '2021-08-14T22:58:59', '2021-08-12T22:58:59', '2021-08-06T22:58:59', '2021-08-04T22:58:59', '2021-07-28T22:58:59', '2021-07-28T22:58:59', '2021-07-22T22:58:59', '2021-07-16T22:58:59', '2021-07-09T22:58:59', '2021-07-07T22:58:59', '2021-07-07T22:58:59', '2021-07-02T22:58:59', '2021-06-30T22:58:59', '2021-06-25T22:58:59', '2021-06-12T22:58:59', '2021-06-10T22:58:59', '2021-06-09T22:58:59', '2021-06-03T22:58:59', '2021-05-27T22:58:59', '2021-05-09T22:58:59', '2021-05-06T22:58:59', '2021-04-30T22:58:59', '2021-04-13T22:58:59', '2021-04-10T22:58:59', '2021-04-07T22:58:59', '2021-03-28T22:58:59', '2021-03-25T22:58:59', '2021-03-18T22:58:59', '2021-03-12T22:58:59', '2021-03-10T22:58:59', '2021-03-06T22:58:59', '2021-03-05T22:58:59', '2021-02-16T22:58:59', '2021-02-10T22:58:59', '2021-02-05T22:58:59', '2021-01-02T22:58:59', '2020-12-04T22:58:59', '2020-07-29T22:58:59', '2020-07-01T22:58:59', '2020-06-24T22:58:59', '2020-06-06T22:58:59', '2020-06-05T22:58:59', '2020-06-03T22:58:59', '2020-05-30T22:58:59', '2020-05-29T22:58:59', '2020-05-28T22:58:59', '2020-05-23T22:58:59', '2020-05-22T22:58:59', '2020-05-21T22:58:59', '2020-05-16T22:58:59', '2020-05-14T22:58:59', '2020-04-29T22:58:59', '2020-04-23T22:58:59', '2020-04-22T22:58:59', '2020-04-12T22:58:59', '2020-04-10T22:58:59', '2020-04-01T22:58:59', '2020-04-01T22:58:59', '2020-03-20T22:58:59', '2020-03-06T22:58:59', '2020-02-28T22:58:59', '2020-02-16T22:58:59', '2020-02-15T22:58:59', '2020-02-08T22:58:59', '2020-02-06T22:58:59', '2020-02-05T22:58:59', '2020-01-30T22:58:59', '2020-01-29T22:58:59', '2020-01-18T22:58:59', '2020-01-17T22:58:59', '2020-01-11T22:58:59', '2020-01-10T22:58:59', '2020-01-10T22:58:59', '2020-01-09T22:58:59', '2020-01-03T22:58:59', '2019-12-14T22:58:59', '2019-12-12T22:58:59', '2019-12-06T22:58:59', '2019-11-28T22:58:59', '2019-11-20T22:58:59', '2019-11-15T22:58:59', '2019-11-09T22:58:59', '2019-10-23T22:58:59', '2019-10-10T22:58:59', '2019-10-02T22:58:59', '2019-09-21T22:58:59', '2019-09-18T22:58:59', '2019-09-14T22:58:59', '2019-09-13T22:58:59', '2019-09-06T22:58:59', '2019-08-31T22:58:59', '2019-07-26T22:58:59', '2019-07-24T22:58:59', '2019-06-27T22:58:59', '2019-06-20T22:58:59', '2019-06-06T22:58:59', '2019-05-29T22:58:59', '2019-05-15T22:58:59', '2019-05-08T22:58:59', '2019-05-03T22:58:59', '2019-05-01T22:58:59', '2019-04-27T22:58:59', '2019-04-24T22:58:59', '2019-04-18T22:58:59', '2019-04-13T22:58:59', '2019-04-06T22:58:59', '2019-03-22T22:58:59', '2019-03-21T22:58:59', '2019-03-20T22:58:59', '2019-03-07T22:58:59', '2019-03-02T22:58:59', '2019-02-16T22:58:59', '2019-01-26T22:58:59', '2019-01-23T22:58:59', '2019-01-10T22:58:59', '2019-01-09T22:58:59', '2019-01-05T22:58:59', '2018-12-14T22:58:59', '2018-12-06T22:58:59', '2018-11-29T22:58:59', '2018-11-23T22:58:59', '2018-11-21T22:58:59']

到目前为止，我已经尝试使用库 rfc3339 中的 rfc3339 函数

start_date = rfc3339(start_date, utc=True, use_system_timezone=False) 这会导致以下错误TypeError: 'module' object is not callable

还有其他解决方案吗？谢谢

【问题讨论】：

标签： python date datetime time

【解决方案1】：

根据该错误消息，您可能已经完成了import rfc3339，而不是from rfc3339 import rfc3339。你不能调用模块（正如它告诉你的那样）。

也就是说，如果你所有的字符串都是YYYY-MM-DDTHH:mm:ss 格式并且你想要YYYY-MM-DDTHH:mm:ssZ，为什么不只是......

z_dates = [date + "Z" for date in start_date]

【讨论】：

谢谢@AKX。你的建议确实解决了问题。但是，如果日期位于 df tucker_df 中的列 start_date 而不是列表 tucker_df$start_date = [date + ".000Z" for date in tucker_df$start_date] 中，则会导致错误 Error: unexpected '[' in "tucker_df$end_date = ["。是否有适用于列和列表的解决方案？
该问题源于 Python 中的标识符中不允许使用美元符号这一事实。重新分配数据框系列时，此表达式将起作用（尽管速度不是最佳）。
我很愚蠢...同时在 R 和 Python 中工作，却忘记了 python 应该是tucker_df["start_date"] = [date + ".000Z" for date in tucker_df["start_date"]]。再次感谢@AKX
@MarcoLiedecke 不客气。如果对您有帮助，请将此答案标记为已接受！