【发布时间】:2017-06-28 02:15:02
【问题描述】:
这些是我目前的数据
ACCOUNT NUMBER PRODUCT STATUS RANK DESIGN
1 530033 Wealth Services Closed 1 Manual
2 530033 Wealth Services Closed 2 Manual
3 530033 Wealth Services Closed 3 Manual
4 530033 Wealth Services Closed 4 Manual
5 534656 Initial Escrow Open 1 Manual
6 534656 Initial Escrow Open 2 Manual
7 535161 Markets Integrity Closed 1 Manual
8 538379 Prepaid Cards Closed 1 Manual
9 538379 Prepaid Cards Closed 2 Manual
10 538379 Prepaid Cards Closed 3 Manual
11 538379 Prepaid Cards Closed 4 Manual
12 538915 Uploaded Cards Open 1 Manual
13 538915 Uploaded Cards Open 2 Manual
14 538915 Uploaded Cards Open 3 Manual
我想创建一个列来唯一计算每个重复的帐户号。比如账号530033出现了四次,我想把每一个530033算为一个,和其他账号534656一样出现两次才算一个。
我已经尝试了以下方法,但这些都不起作用。
count(distinct(Account Number))
count(distinct(Account Number) for Account Number)
聚合列等于 TOTAL、COUNT 或 AUTOMATIC。
我将使用这些数据创建一个交叉表。我的交叉表给我的总数为 14,因为它计算了所有重复的帐号。因为所有帐号都有十四行。但实际上只有 5 个帐号(530033、534656、535161、538379 和 53891)
TOTAL Open Closed
Wealth Services 4 4
Initial Escrow 2 2
Markets Integrity 1 1
Prepaid Cards 4 4
Uploaded Cards 3 3
TOTAL 14
理想情况下应该是这样的。
TOTAL Open Closed
Wealth Services 1 1
Initial Escrow 1 1
Markets Integrity 1 1
Prepaid Cards 1 1
Uploaded Cards 1 1
TOTAL 5
我应该创建一个名为“帐号的唯一计数”的新列吗?但是如何单独计算帐号?
我是否必须创建另一个具有唯一帐号的表,然后将两个表内部连接?
【问题讨论】: