如果两对具有相同的值，则合并同一数组中的两对

Question

我有以下对，它们在同一个数组中：

[
 ["ID" => 0, "User" => "Test" , "Type" => 3, "Target" => "Caris"],
 ["ID" => 1, "User" => "Test1", "Type" => 3, "Target" => "Caris"],
 ["ID" => 2, "User" => "Test2", "Type" => 4, "Target" => "Shirone"],
 ["ID" => 3, "User" => "Test3", "Type" => 3, "Target" => "Caris"]
]

我想获取它们的种类，所以我使用以下代码：

$SortList = [];

foreach($Notif as $Key => $Value)
            array_push($SortList, ['Type'   => $Value['Type'], 
                                   'Target' => $Value['Target']]);

然后得到这个：

[
 ["Type" => 3, "Target" => "Caris"], 
 ["Type" => 3, "Target" => "Caris"], 
 ["Type" => 4, "Target" => "Shirone"],
 ["Type" => 3, "Target" => "Caris"]
]

但我真正想要的是这样的：

[
 ["Type" => 3, "Target" => "Caris"], 
 ["Type" => 4, "Target" => "Shirone"]
]

如果它们的值相同，我想合并它们，

(array_merge()好像只能用于非配对)

我怎样才能像上面那样合并它们？

Answer 1

$SortList = [];
foreach($Notif as $Key => $Value) {
    // Just save only value for the same pair, use them concatenated as the key
    $SortList[$Value['Type']."_".$Value['Target']] =
      array('Type' => $Value['Type'], 'Target' => $Value['Target']);
}
// remove extra stuff (the keys) that was added to prevent duplicates
$SortList = array_values($SortList);