如何向 Mulesoft 报告错误答案

【问题标题】：How to report a bug to Mulesoft如何向 Mulesoft 报告错误
【发布时间】：2021-05-09 00:03:50
【问题描述】：

我在 Mule 4 组件中发现了以下错误。如何向 Mulesoft 报告此问题？

Mule 4 XML 模块 1.2.3 引入了一个错误，导致模块中出现错误的 Mule 错误。

在验证无效的 XML 有效负载（非 xml 字符串、带有未闭合或未配对标签的“XML”等）1.2.2 版组件时会引发 mule 错误XML-MODULE:INVALID_INPUT_XML，但使用 1.2.3 版组件现在的错误是XML-MODULE:TRANSFORMATION。

问题似乎是该模块的版本 1.2.3 删除了对 XMLUtils.toDOMNode 的调用，该调用用于对消息进行初始验证，并在处理无效 XML 时抛出类 InvalidInputXmlException 异常。

XML 模块：1.2.2

public class SchemaValidatorOperation extends PooledTransformerOperation<SchemaValidatorOperation.SchemaKey, Validator> {
  private LSResourceResolver resourceResolver = (LSResourceResolver)new MuleResourceResolver();
  
  @Validator
  @Execution(ExecutionType.CPU_INTENSIVE)
  @Throws({SchemaValidatorErrorTypeProvider.class})
  public void validateSchema(@Path(type = PathModel.Type.FILE, acceptedFileExtensions = {"xsd"}) String schemas, @Optional(defaultValue = "W3C") SchemaLanguage schemaLanguage, @Content(primary = true) InputStream content, @Config XmlModule config) {
    Node node = XMLUtils.toDOMNode(content, this.documentBuilderFactory);
    withTransformer(new SchemaKey(schemas, schemaLanguage.getLanguageUri(), this.expandEntities), validator -> {
          validator.setResourceResolver(this.resourceResolver);
          final List<SchemaViolation> errors = new LinkedList<>();
          validator.setErrorHandler(new ErrorHandler() {
                public void warning(SAXParseException exception) {}
                
                public void error(SAXParseException exception) {
                  trackError(exception);
                }
                
                public void fatalError(SAXParseException exception) {
                  trackError(exception);
                }
                
                private void trackError(SAXParseException exception) {
                  errors.add(new SchemaViolation(exception.getLineNumber(), exception.getColumnNumber(), exception.getMessage()));
                }
              });
          try {
            validator.validate(new DOMSource(node));
          } catch (SAXParseException e) {
            throw new TransformationException("Failed to validate schema. " + e.getMessage(), e);
          } catch (IOException e) {
            throw new InvalidInputXmlException("Could not validate schema because the input was not valid XML. " + e.getMessage(), e);
          } 
          if (!errors.isEmpty())
            throw new SchemaValidationException("Input XML was not compliant with the schema. Check this error's Mule message for the list of problems (e.g: #[error.errorMessage.payload[0].description)", errors); 
          return null;
        });
  }

XML 模块：1.2.3

public class SchemaValidatorOperation extends PooledTransformerOperation<SchemaValidatorOperation.SchemaKey, Validator> {
  private LSResourceResolver resourceResolver = (LSResourceResolver)new MuleResourceResolver();
  
  @Validator
  @Execution(ExecutionType.CPU_INTENSIVE)
  @Throws({SchemaValidatorErrorTypeProvider.class})
  public void validateSchema(@Path(type = PathModel.Type.FILE, acceptedFileExtensions = {"xsd"}) String schemas, @Optional(defaultValue = "W3C") SchemaLanguage schemaLanguage, @Content(primary = true) InputStream content, @Config XmlModule config) {
    withTransformer(new SchemaKey(schemas, schemaLanguage.getLanguageUri(), this.expandEntities), validator -> {
          validator.setResourceResolver(this.resourceResolver);
          final List<SchemaViolation> errors = new LinkedList<>();
          validator.setErrorHandler(new ErrorHandler() {
                public void warning(SAXParseException exception) {}
                
                public void error(SAXParseException exception) {
                  trackError(exception);
                }
                
                public void fatalError(SAXParseException exception) {
                  trackError(exception);
                }
                
                private void trackError(SAXParseException exception) {
                  errors.add(new SchemaViolation(exception.getLineNumber(), exception.getColumnNumber(), exception.getMessage()));
                }
              });
          try {
            SAXParserFactory spf = SAXParserFactory.newInstance();
            spf.setNamespaceAware(true);
            spf.setFeature("http://xml.org/sax/features/external-general-entities", this.expandEntities.isAcceptExternalEntities());
            spf.setFeature("http://xml.org/sax/features/external-parameter-entities", this.expandEntities.isAcceptExternalEntities());
            spf.setFeature("http://apache.org/xml/features/disallow-doctype-decl", !this.expandEntities.isExpandInternalEntities());
            spf.setFeature("http://apache.org/xml/features/nonvalidating/load-external-dtd", this.expandEntities.isExpandInternalEntities());
            validator.validate(new SAXSource(spf.newSAXParser().getXMLReader(), new InputSource(content)));
          } catch (SAXParseException e) {
            throw new TransformationException("Failed to validate schema. " + e.getMessage(), e);
          } catch (IOException e) {
            throw new InvalidInputXmlException("Could not validate schema because the input was not valid XML. " + e.getMessage(), e);
          } 
          if (!errors.isEmpty())
            throw new SchemaValidationException("Input XML was not compliant with the schema. Check this error's Mule message for the list of problems (e.g: #[error.errorMessage.payload[0].description)", errors); 
          return null;
        });
  }

并不是说XMLUtils.toDOMNode 是完美的，因为它捕获了任何异常，但至少在尝试验证不正确的 xml 时检测实例很有用。

XMLUtils.toDOMNode

public class XMLUtils {
  public static Node toDOMNode(InputStream src, DocumentBuilderFactory factory) {
    return toDOMNode(src, factory, null);
  }
  
  public static Node toDOMNode(InputStream src, DocumentBuilderFactory factory, EntityResolver entityResolver) {
    try {
      DocumentBuilder documentBuilder = factory.newDocumentBuilder();
      if (entityResolver != null)
        documentBuilder.setEntityResolver(entityResolver); 
      return documentBuilder.parse(src);
    } catch (Exception e) {
      throw new InvalidInputXmlException("Cannot parse input XML because it is invalid.", e);
    } 
  }
}

【问题讨论】：

到目前为止你尝试过什么？你被困在哪里了？

标签： mulesoft mule4

【解决方案1】：

对于像 XML 模块这样的 Mule 开源组件，您可以在 MuleSoft 开放跟踪器中打开 JIRA 票证：https://www.mulesoft.org/jira/projects/MULE。 XML 模块的源位于https://github.com/mulesoft/mule-xml-module，因此如果您创建了一个，则可以将推送请求附加到票证。

如果您是 MuleSoft 的当前客户，您可以直接联系他们的支持。

【讨论】：