获取推送通知令牌 - iOS 10、Swift 3答案

【问题标题】：Get the push notification token - iOS 10, Swift 3获取推送通知令牌 - iOS 10、Swift 3
【发布时间】：2017-01-26 16:06:25
【问题描述】：

如何在 iOS 10 中从新的 xCode 8、Swift 3 获取设备令牌？

这里是注册通知的代码：

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {    

    DispatchQueue.main.async {
        let settings = UIUserNotificationSettings(types: [.badge, .sound, .alert], categories: nil)
        UIApplication.shared.registerUserNotificationSettings(settings)
    }
    return true
}

func application(_ application: UIApplication, didRegister notificationSettings: UIUserNotificationSettings) {

    if notificationSettings.types != UIUserNotificationType() {
        application.registerForRemoteNotifications()
    }
}

在这里我得到了令牌，但我得到了以下错误

Cannot invoke initializer for type 'UnsafePointer<CChar>' with an argument list of type '(UnsafeRawPointer)':

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let chars = UnsafePointer<CChar>((deviceToken as NSData).bytes)
    var token = ""

    for i in 0..<deviceToken.count {
        token += String(format: "%02.2hhx", arguments: [chars[i]])
    }

    print("Registration succeeded!")
    print("Token: ", token)
}

谁能帮我解决？

【问题讨论】：

stackoverflow.com/questions/37956482/…的可能重复
您可以在目标 C 中点击此链接，但您可以了解一些想法 stackoverflow.com/questions/39572897/…

标签： push-notification notifications swift3 ios10

【解决方案1】：

由于您可能在不同的方法中需要此令牌（例如 firebase、web 参与、分支等），您可以使用自定义类从包含 data 和 string 的数据中初始化 APNS

public class APNS {
    public init(deviceToken data: Data) {
        self.data = data
        self.string = data.map { data in String(format: "%02.2hhx", data) } .joined()
    }

    public let data: Data
    public let string: String
}

那么你可以在任何你需要的地方使用它：

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    let token = APNS(deviceToken: deviceToken)
    print(token.string)
}

【讨论】：

【解决方案2】：

一行：

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    let apnsDeviceToken = deviceToken.map {String(format: "%02.2hhx", $0)}.joined()
}

From this tutorial.

或者模块化/封装/OOP方式：

extension Data {
  var string: String {
    return map {String(format: "%02.2hhx", $0)}.joined()
  }
}

那么你可以这样做：

let token = deviceToken.string

【讨论】：

【解决方案3】：

来自 Mixpanel 库的代码

    let tokenChars = (deviceToken as NSData).bytes.assumingMemoryBound(to: CChar.self)
    var tokenString = ""
    for i in 0..<deviceToken.count {
        tokenString += String(format: "%02.2hhx", arguments: [tokenChars[i]])
    }

【讨论】：

【解决方案4】：

获取推送通知令牌的工作代码 - iOS 11 或更高版本，Swift 4

请求用户权限

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {

    let notificationTypes: UIUserNotificationType = [UIUserNotificationType.alert,UIUserNotificationType.badge, UIUserNotificationType.sound]
    let pushNotificationSettings = UIUserNotificationSettings(types: notificationTypes, categories: nil)

    application.registerUserNotificationSettings(pushNotificationSettings)
    application.registerForRemoteNotifications()

    return true        
}

获取设备令牌

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let token = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()
    print(token) 
}

出现错误时

func application(_ application: UIApplication, didFailToRegisterForRemoteNotificationsWithError error: Error) {

    print("i am not available in simulator \(error)")
}

【讨论】：

【解决方案5】：

此方法可能会解决您在 iOS 10 及更高版本中的问题：

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    var token = ""
    for i in 0..<deviceToken.count {
        token = token + String(format: "%02.2hhx", arguments: [deviceToken[i]])
    }
    print(token)
}

【讨论】：

我没有投反对票。但也许是因为没有解释为什么/如何 Data 需要像这样转换为 String

【解决方案6】：

它可以工作：

let chars = UnsafePointer<CChar>((deviceToken as NSData).bytes.assumingMemoryBound(to:CChar.self))

谢谢！

【讨论】：

【解决方案7】：

以下 snnipet 正在使用 Eric Aya 解决方案：

let token = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})

感谢大家的帮助:)

【讨论】：

【解决方案8】：

Swift 3 示例取自 raywenderlich.com。

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data){
    let tokenParts = deviceToken.map { data -> String in
        return String(format: "%02.2hhx", data)
    }  
    let token = tokenParts.joined()
    print(token)
}

【讨论】：

【解决方案9】：

面临同样的问题，这是唯一帮助我的事情：

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    let token = String(format: "%@", deviceToken as CVarArg)
        .trimmingCharacters(in: CharacterSet(charactersIn: "<>"))
        .replacingOccurrences(of: " ", with: "")
}

【讨论】：

【解决方案10】：

var pushToken = String(format: "%@", deviceToken as CVarArg)
pushToken = pushToken.trimmingCharacters(in: CharacterSet(charactersIn: "<>"))
pushToken = pushToken.replacingOccurrences(of: " ", with: "")

【讨论】：