未创建 Jquery cookie答案

【问题标题】：Jquery cookie not created未创建 Jquery cookie
【发布时间】：2014-04-11 19:09:19
【问题描述】：

您好，我在 head-tag 中包含了 jquery.cookie-plugin，现在我正在使用这个 sn-p 来测试 cookie：

$(document).ready(function() {
    $userSettings = array(
        "personal_information" = array(
            "name" => "name",
            "last_name" => "lastname"
        ),
        "extra_information" = array(
            "twitter" => "anyName",
            "facebook" => "anyName",
            "website" => "http://domain.com/",
            "programming_languages" => array("JavaScript", "PHP", "Java")
        )
   );
});
// Creating the JSON object
$jsonObject = json_encode($userSettings);

(function($){
        $(document).on('ready', function(){
            //A cookie by the name 'userSettings' now exists with a serialized copy of $userSettings
            $.cookies.set( 'userSettings', <?php echo $jsonObject; ?> );

            //A variable named 'userSettings' now holds the unserialized object, it should be identical to the PHP variable 'userSettings'
            var userSettings = $.cookies.get( 'userSettings' );

            // Do something with the values read from cookie
            console.log(userSettings);
        });
})(jQuery);

但是我的控制台中没有日志，任何人都可以告诉我我做错了什么，因为我在控制台中得到了这个参考：

ReferenceError: invalid assignment left-hand side

$userSettings = array("personal_information" = array(

你好！！

【问题讨论】：

那么，任何答案都有帮助吗？你设法解决了这个问题吗？请更新此 SO 项；也许您可以检查 1 个答案为“正确”...

标签： javascript jquery arrays cookies plugins

【解决方案1】：

试试这个

 <?php 
$userSettings = array(
    "personal_information" = array(
        "name" => "name",
        "last_name" => "lastname"
    ),
    "extra_information" = array(
        "twitter" => "anyName",
        "facebook" => "anyName",
        "website" => "http://domain.com/",
        "programming_languages" => array("JavaScript", "PHP", "Java")
    )
 );

  // Creating the JSON object

$jsonObject = json_encode($userSettings);
  ?>

<script type="text/javascript">
   (function($){
    $(document).on('ready', function(){
        //A cookie by the name 'userSettings' now exists with a serialized copy of $userSettings
        $.cookie.set( 'userSettings', <?php echo $jsonObject; ?> );

        //A variable named 'userSettings' now holds the unserialized object, it should be identical to the PHP variable 'userSettings'
        var userSettings = $.cookie.get( 'userSettings' );

        // Do something with the values read from cookie
        console.log(userSettings);
    });
 })(jQuery);

   </script>

【讨论】：

【解决方案2】：

您必须改用$.cookie()：

(function($){
    $(document).on('ready', function(){

        $.cookie( 'userSettings', '<?php echo $jsonObject; ?>' ); // change here

        var userSettings = $.cookie( 'userSettings' ); // here

        console.log(userSettings);
    });
})(jQuery);

【讨论】：

【解决方案3】：

为什么不直接把它变成一个 JSON 对象：

var userSettings = [{
    "personal_information" : {
        "name" :"name",
        "last_name" : "lastname"
    }},
    {"extra_information" : {
        "twitter" : "anyName",
        "facebook" : "anyName",
        "website" : "http://domain.com/",
        "programming_languages" : ["JavaScript", "PHP", "Java"]
    }
}]

@Jai 是对的：你应该使用 $.cookie() 而不是 get() 和 set()

$.cookie( 'userSettings', JSON.stringify(userSettings));

【讨论】：