在 Python 中使用 LinkedIn API v2 (oauth2) 需要帮助

Question

我使用来自这里的代码https://github.com/ozgur/python-linkedin 以及我的 ID 和密钥。如果我运行此代码并转到 localhost:8080（我使用了此端口），我会收到以下异常：

127.0.0.1 - - [31/Aug/2018 13:25:49] "GET / HTTP/1.1" 200 -
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 65176)
Traceback (most recent call last):
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\socketserver.py", line 647, in process_request_thread
    self.finish_request(request, client_address)
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\socketserver.py", line 357, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\http\server.py", line 646, in __init__
    super().__init__(*args, **kwargs)
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\socketserver.py", line 717, in __init__
    self.handle()
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\http\server.py", line 426, in handle
    self.handle_one_request()
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\http\server.py", line 414, in handle_one_request
    method()
  File "C:/Users/osads/PycharmProjects/python-linkedin-master/examples/http_api.py", line 60, in do_GET
    open_new_tab(liw.authentication.authorization_url)
  File "C:\Users\osads\PycharmProjects\python-linkedin-master\linkedin\linkedin.py", line 101, in authorization_url
    qsl = ['%s=%s' % (quote(k), quote(v)) for k, v in qd.items()]
  File "C:\Users\osads\PycharmProjects\python-linkedin-master\linkedin\linkedin.py", line 101, in <listcomp>
    qsl = ['%s=%s' % (quote(k), quote(v)) for k, v in qd.items()]
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\urllib\parse.py", line 791, in quote
    return quote_from_bytes(string, safe)
  File "C:\Users\osads\AppData\Local\Programs\Python\Python37-32\lib\urllib\parse.py", line 816, in quote_from_bytes
    raise TypeError("quote_from_bytes() expected bytes")
TypeError: quote_from_bytes() expected bytes

如何解决这个问题？

UPD：来自linkedin.py的代码

 @property
    def authorization_url(self):
        qd = {'response_type': 'code',
              'client_id': self.key,
              'scope': (' '.join(self.permissions)).strip(),
              'state': self.state or self._make_new_state(),
              'redirect_uri': self.redirect_uri}
        # urlencode uses quote_plus when encoding the query string so,
        # we ought to be encoding the qs by on our own.
        qsl = ['%s=%s' % (quote(k), quote(v)) for k, v in qd.items()]
        return '%s?%s' % (self.AUTHORIZATION_URL, '&'.join(qsl))

Answer 1

本条目的值

'state': self.state or self._make_new_state()

是一个布尔值。 quote 需要一个字符串。

简而言之，这是您的错误：

from urllib.parse import quote
quote(True)

我不知道你到底在做什么，但这会修复你的错误（并可能产生几个新错误）。

'state': str(self.state or self._make_new_state())