【发布时间】：2018-05-05 03:26:28
【问题描述】：
所以仍在学习，但我从下面的代码中收到了未经授权的错误 401。我知道 OAuth 标头在邮递员中工作，所以我假设 POST 请求 / Auth 标头有问题？有什么想法吗？
//set timestamp
Long timestamp = System.currentTimeMillis()/1000;
//set nonce ***** call from main system*************************************************************
String aString = randomAlphaNumeric(11);
// other stuff
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new StringHttpMessageConverter());
HttpHeaders headers = new HttpHeaders();
String url = "aURL";
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
// String auth = Base64.getEncoder().encodeToString(credentials.getBytes());
List<NameValuePair> oauthHeaders = new ArrayList<>(9);
oauthHeaders.add(new BasicNameValuePair("oauth_consumer_key", "aKey"));
oauthHeaders.add(new BasicNameValuePair("oauth_nonce", aString));
oauthHeaders.add(new BasicNameValuePair("oauth_timestamp", String.valueOf(timestamp)));
oauthHeaders.add(new BasicNameValuePair("oauth_signature_method", "HMAC-SHA1"));
oauthHeaders.add(new BasicNameValuePair("oauth_version", "1.0"));
//generate signature
//encode
String encodedURL = encode(oauthHeaders.toString());
System.out.println("encoded URL:" +encodedURL);
//form base string
String baseString = "POST&"+encode(url).toString()+encodedURL;
System.out.println("Base String: "+baseString);
//form signature
byte[] byteHMAC = null;
try {
Mac mac = Mac.getInstance("HmacSHA1");
SecretKeySpec spec;
if (null == secretKey) {
String signingKey = encode(secretKey) + '&';
spec = new SecretKeySpec(signingKey.getBytes(), "HmacSHA1");
} else {
String signingKey = encode(secretKey) + '&' + encode(secretKey);
spec = new SecretKeySpec(signingKey.getBytes(), "HmacSHA1");
}
mac.init(spec);
byteHMAC = mac.doFinal(baseString.getBytes());
} catch (Exception e) {
e.printStackTrace();
}
String signature = new BASE64Encoder().encode(byteHMAC);
System.out.println("oauth signature: "+signature);
//set signature to params
oauthHeaders.add(new BasicNameValuePair("oauth_signature", signature));
String test = "OAuth "+oauthHeaders.toString();
headers.set("Authorization", test);
MultiValueMap<String, String> map = new LinkedMultiValueMap<String, String>();
map.add("Name",name.toString());
map.add("Region",region.toString());
HttpEntity<MultiValueMap<String, String>> requestEntity= new HttpEntity<MultiValueMap<String, String>>(headers, map);
System.out.println(requestEntity);
ResponseEntity<String> response= restTemplate.exchange(url ,HttpMethod.POST, requestEntity, String.class);
System.out.println(response.toString());
HttpStatus status = response.getStatusCode();
status.toString();
if(status.equals("200")){
Notification.show("Employer" + name +" added successfully");
}
else{
Notification.show("Unsuccessful, error: "+status);
}
}
出于显而易见的原因删除了 URL 和使用者密钥/签名。
以下系统输出也可能有所帮助：
编码参数： %5Boauth_consumer_key%3aKey%2C%20oauth_nonce%3DWZU8H1B5JA6%2C%20oauth_timestamp%3D1511621759%2C%20oauth_signature_method%3DHMAC-SHA1%2C%20oauth_version%3D1.0%5D
基本字符串：POST&https%3A%2F%2Fapi.test.payrun.io%2FEmployer%5Boauth_consumer_key%3aKey%2C%20oauth_nonce%3DWZU8H1B5JA6%2C%20oauth_timestamp%3D1511621759%2C%20oauth_signature_method%3DHMAC-SHA1%2C%20%3DHMAC-SHA1%2C%20 3D1.0%5D
oauth 签名：DlRJGSzgRIItzz+LzMbgnIfbOqU=
【问题讨论】：
-
你试过用
Authorization（注意Z，而不是S）作为标题名称吗？ -
刚刚更改并重新运行代码....仍然收到 401 Unauthorized。