【发布时间】:2021-06-26 00:26:15
【问题描述】:
我有一个小客户端,我正试图与我编写的回显服务器通信,它的代码如下:
import zmq
con = zmq.Context()
back: zmq.Socket = con.socket(zmq.ROUTER)
back.setsockopt(zmq.IDENTITY, b"\x34")
back.connect("tcp://localhost:19802")
sock: zmq.Socket = con.socket(zmq.DEALER)
sock.setsockopt(zmq.IDENTITY, b"\x35")
sock.connect("tcp://localhost:19801")
sock.send_multipart([b"1", b"2", b"3", b"4", b"5"])
msg = back.recv_multipart()
print(msg)
这工作正常,客户端打印[b'broker1', b'5', b'1', b'2', b'3', b'4', b'5']。然后我想看看我是否可以用zmq.async 做到这一点。于是我修改了代码如下:
import zmq
import zmq.asyncio
import asyncio
con = zmq.asyncio.Context()
back: zmq.asyncio.Socket = con.socket(zmq.ROUTER)
back.setsockopt(zmq.IDENTITY, b"\x34")
back.connect("tcp://localhost:19802")
sock: zmq.asyncio.Socket = con.socket(zmq.DEALER)
sock.setsockopt(zmq.IDENTITY, b"\x35")
sock.connect("tcp://localhost:19801")
async def rcv():
await sock.send_multipart([b"1", b"2", b"3", b"4", b"5"])
msg = await back.recv_multipart()
print(msg)
asyncio.run(rcv())
现在服务器仍然收到[b"5", b"1", b"2", b"3", b"4", b"5"]。但是客户端挂在msg = await back.recv_multipart()。
为什么会这样?任何指针表示赞赏。
【问题讨论】: