CakePHP 3.6.11：视图中连接表的访问属性

Question

我有这张桌子：

客户[id, name, surname, phone, text, balance, created]

service_types[id, title, price, length, is_subscription, created]

customer_service_types[id, customer_id, service_type_id, price, created]

在view.ctp 中，我想查看分配给当前客户的所有Services。

Bake 在CustomersController.php 中创建了这个view function

public function view($id = null)
    {
        $customer = $this->Customers->get($id, [
            'contain' => ['CustomerServiceTypes']
        ]);

        $this->set('customer', $customer);
    }

在view.ctp 中，我想显示service_type -> title，所以我尝试这样做：

<td><?=$customerServiceTypes->service!==null ? h($customerServiceTypes->service->title) : '' ?></td>

但它总是显示空白。我怎样才能改变它才能工作？

Answer 1

改变视图功能如下：

$customer = $this->Customers->get($id, [
            'contain' => ['CustomerServiceTypes' => ['ServiceTypes']]
        ]);


        $this->set('customer', $customer);

在view.ctp中：

<td><?= h($customerServiceTypes->service_type->title) ?></td>