XML 到对象映射器答案

【问题标题】：XML to Objects mapperXML 到对象映射器
【发布时间】：2012-11-28 12:07:15
【问题描述】：

我正在尝试制作一种应用程序文件格式解析器和生成器。应用程序使用带有自定义 DTD 的 xml 文件。目前我正在考虑使用nokogiri 编写对象映射器来将xml 解析为对象并使用这些对象来生成xml。我尝试过 HappyMapper 和 xml-mapping，但它们没有使用完整的 xml 格式。所以目前我已经做了这个，但我认为它的设计有点糟糕。

http://pastie.org/5393012

【问题讨论】：

我正在寻找最好的方法。现在我这样做：github.com/gcds/libeagle
请在问题中包含您的源代码，而不是指向它的链接。如果/当链接断开时，您的问题将不是很有用。

标签： ruby xml orm dtd

【解决方案1】：

你可以使用 C# 和 XMLSerilaizer，它是最好的。示例如下：

---------------just a lot of entity ----------------------
using System;
namespace BuilderSerialization {
public class Address {
public Address() {}
public string Address1;
public string Address2;
public string City;
public string State;
public string Zip;
public string Country;
} }
using System;
namespace BuilderSerialization {
public class Author {
public Author() { }
public string FirstName;
public string MiddleName;
public string LastName;
public string Title;
public string Gender;
public Address AddressObject;
} }

namespace BuilderSerialization {
public class Book {
public Book() { }
public string Title;
public Author AuthorObject;
public string ISBN;
public double RetailPrice;
public string Publisher;
}}
-------------------------------------------------------
using System;
using System.Xml.Serialization;
using System.IO;
namespace BuilderSerialization {
class TestClass {
static void Main(string[] args) {
Book BookObject = new Book();
XmlSerializer ser = new XmlSerializer(typeof(Book));
TextWriter writer = new StreamWriter("booktest.xml");
BookObject.Title = "Practical LotusScript";
BookObject.ISBN = "1884777767 ";
BookObject.Publisher = "Manning Publications";
BookObject.RetailPrice = 43.95;
BookObject.AuthorObject = new Author();
BookObject.AuthorObject.FirstName = "Tony";
BookObject.AuthorObject.LastName = "Patton";
BookObject.AuthorObject.Gender = "Male";
BookObject.AuthorObject.AddressObject = new Address();
BookObject.AuthorObject.AddressObject.Address1 = "1 Main Street";
BookObject.AuthorObject.AddressObject.City = "Anywhere";
BookObject.AuthorObject.AddressObject.State = "KY";
BookObject.AuthorObject.AddressObject.Zip = "40000";
BookObject.AuthorObject.AddressObject.Country = "USA";
ser.Serialize(writer, BookObject);
writer.Close();
} } }

之后你会得到 XML：

<?xml version="1.0" encoding="utf-8"?>
<Book xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Title>Practical LotusScript</Title>
<AuthorObject>
<FirstName>Tony</FirstName>
<LastName>Patton</LastName>
<Gender>Male</Gender>
<AddressObject>
<Address1>1 Main Street</Address1>
<City>Anywhere</City>
<State>KY</State>
<Zip>40000</Zip>
<Country>USA</Country>
</AddressObject>
</AuthorObject>
<ISBN>1884777767 </ISBN>
<RetailPrice>43.95</RetailPrice>
<Publisher>Manning Publications</Publisher>
</Book>

【讨论】：

OP 正在寻找 Ruby 解决方案。
如果您将 Ironruby 视为一种红宝石解决方案，它仍然可以工作。