当我插入参数时，我的 php 代码在邮递员上不起作用

Question

嘿，伙计们，我下面的 php 代码在邮递员上不起作用，每当我输入电子邮件和密码参数时，它都不起作用，并且只显示一个错误，它下面显示 {success:0 , message:invalid request}，我我从数据库中给出正确的参数，我的数据库表名是用户，列是 id、name、email、password、type。请检查我在 php 中的新代码。请帮忙

    <?php header('Access-Control-Allow-Origin: *'); ?>
<?php header('Access-Control-Allow-Headers: Origin,X-Requested-With,Content-Type,Accept'); ?>
<?php header('Access-Control-Allow-Methods: POST,GET,OPTIONS,PUT'); ?>
<?php 
 session_start();
include_once('configdb.php');
error_reporting(E_ALL);
$response = array();
if(isset($_POST['email']) && isset($_POST['password'])){
$name= $_POST['email'];
$password=$_POST['password'];
$result=mysqli_query($conn,"SELECT * FROM users WHERE email='$email' AND password='$password'");
 $row=mysqli_fetch_assoc($result);
 $count=mysqli_num_rows($result);
 if($count==1){
    $_SESSION['users']=array(
   'email'=>$row['email'],
   'password'=>$row['password'],
   'name'=>$row['name'],
   'type'=>$row['type']
   );
   $role=$_SESSION['users']['type'];
   //Redirecting User Based on Role
    switch($role){
  case 'user':
 // header('location:user.php');
  $response["success"] = 1;
   $response["message"] = "user.";
  break;
  case 'admin':
 // header('location:admin.php');
  $response["success"] = 1;
   $response["message"] = "admin.";
  break;
 }
 }else{
 $response["success"] = 0;
   $response["message"] = "PASSWORD OR EMAIL DOES NOT EXIST.";
 }
}
else{
$response["success"] = 0;
   $response["message"] = "INVALID REQUEST.";

}
header('Content-type: application/json');
  echo json_encode($response);
  mysqli_close($conn);

?>

你能告诉我错误是什么吗？

这是我的请求POSTMAN REQUEST

Answer 1

您在查询中使用了$email 变量，但您将密码保存在$name 变量中。