Sequelize - 如何添加/更新与软删除行的主键相同的行

Question

我正在使用续集 ORM。我有一个表模型，我们通过paranoid: true 启用了软删除。

问题：有没有办法进行 upsert，如果对象已经存在于表中但被软删除，它只会清除 deletedAt 列？

示例设置：model.js

const Sequelize = require('sequelize')
const sequelize = new Sequelize(
  dbName,
  username,
  password,
  {
    host,
    dialect: 'mysql',
    port
  }
)

const model =  sequelize.define(
  'sample_table',
  {
    uid: {
      type: Sequelize.STRING(60),
      allowNull: false
      primaryKey: true
    },
    deletedAt: {
      type: Sequelize.Date,
      allowNull: true,
      default: null
    }
  },
  {
    tableName: 'sample_table'
    deletedAt: true,
    paranoid: true
  }
)

示例用法：

const model = require('./model.js')

(async () => {
  const myModel = await model.create({
    uid: 'sample-uid'
  })

  await myModel.destroy()

  // error is encountered because uid already exists
  await model.create({
    uid: 'sample-uid'
  })
})()

Answer 1

是的，但您应该手动执行（例如，添加 catch 以创建方法并使用 .restore() 清除 deletedAt 列）。

或者您可以在 uid + deletedAt 上添加主键，您的代码应该可以正常工作。

const model = require('./model.js')

(async () => {
  const myModel = await model.create({
    uid: 'sample-uid'
  })

  await myModel.destroy()

  // if primary key uid and deletedAt then no error here
  await model.create({
    uid: 'sample-uid'
  })
})()