向 ArrayList 添加多个参数

Question

我无法确定这项任务。我只是在寻找特定问题的答案，因为在向数组列表添加东西时我似乎有点迷茫。我有一个带有 add 方法的“Gym”类，它应该从 Member 类创建一个“Member”对象。

public class Gym {

    private String gymName;              // Identifies the name of the gym.
    private ArrayList<Member> members;   // A list of member objects.
    private double[] gymRates;           // A map that relates membership type to its fee.
    private double trainerRate;          // indicates rate charge for one hour with PT.

    /**
     * Add a new member to a gym's list of members.
     * 
     * @param hoursQ1    number of personal trainer hours the member had for quarter one.
     * @param hoursQ2    number of personal trainer hours the member had for quarter two.
     * @param hoursQ3    number of personal trainer hours the member had for quarter three.
     * @param hoursQ4    number of personal trainer hours the member had for quarter four.
     */
    public void addMember(String firstName, String lastName, MembershipType memberType, int hoursQ1, int hoursQ2,
            int hoursQ3, int hoursQ4) {
        members.add(new Member(firstName, lastName, memberType, hoursQ1, hoursQ2, hoursQ3, hoursQ4));
    }

    /**
     * Add a specified member to a gym's list of members.
     * 
     * @param member     the member to add.
     */
    public void addMember(Member member) {
        Member.add(member);
    }
}

public class Member {
    private String firstName;
    private String lastName;
    private MembershipType memberType;
    private int[] trainerHours = new int[4];
}

据我了解，错误（参数长度不同）是因为该参数具有 Q1-Q4 小时数，而我没有正确地将它们初始化到 trainerHours 数组中？

另外，我的 trainerHours 数组应该使用枚举类型类“Quarter”作为索引 Q1、Q2、Q3、Q4。这个我也没搞清楚。。 抱歉格式化，这里也有问题！ ;)

Answer 1

你的代码有两个问题：

• 首先，当您调用 new Member (...) 时，未定义该函数，因为您尚未为类 Member 定义具有这些参数的构造函数
• 第二，你的第二个addMember方法不对，应该是members.add(...)而不是Member.add

Answer 2

我应该为成员类创建以下构造函数：

public Member(String pFirstName, String pLastName, MembershipType pMemberType, int hoursQ1, int hoursQ2, int hoursQ3, int hoursQ4){
    firstName = pFirstName;
    lastNam = pLastName;
    memberType = pMemberType;
    trainerHours[0] = hoursQ1;
    trainerHours[1] = hoursQ2;
    trainerHours[2] = hoursQ3;
    trainerHours[3] = hoursQ4;
}