如何在 Javascript 中打破承诺

Question

我已经开发了一个命令行程序及其工作，但是当它完成时它没有完成。我必须 control+c 一个 shell 才能退出

我是 javascript 新手。我必须通过回调来说明程序已完成吗？

我的代码：

importer.then(function (csvData) {
    var mySqlConnection = new MySqlConnection(config['phpipam-db']['host'], config['phpipam-db']['user'], config['phpipam-db']['password'], config['phpipam-db']['database']);
    var connection = mySqlConnection.getConnection();

    mySqlConnection.selectSubnets(connection).then(function (customerFolders) {
        var ipv6Data = manager.getIpv6CustomerSubnetsInsertData(csvData, customerFolders);
        var ipv4Data = manager.getIpv4CustomerSubnetsInsertData(csvData, customerFolders);

        mySqlConnection.insertIpv6Subnets(ipv6Data);
    });
});

Answer 1

在var connection = mySqlConnection.getConnection(); 和mySqlConnection.insertIpv6Subnets(ipv6Data); 之后添加console.log 语句。

如果它们被执行，则问题不在您发布的代码中。

如果没有，您必须检查您的承诺是否得到履行。

Answer 2

这些方法：manager.getIpv6CustomerSubnetsInsertData、mySqlConnection.insertIpv6Subnets 是否也返回承诺？

如果你像这样修改你的代码，你能在控制台中看到 Done 吗？

importer.then(function (csvData) {
  var mySqlConnection = new MySqlConnection(config['phpipam-db']['host'], config['phpipam-db']['user'], config['phpipam-db']['password'], config['phpipam-db']['database']);
  var connection = mySqlConnection.getConnection();

  return mySqlConnection.selectSubnets(connection).then(function (customerFolders) {
    var ipv6Data = manager.getIpv6CustomerSubnetsInsertData(csvData, customerFolders);
    var ipv4Data = manager.getIpv4CustomerSubnetsInsertData(csvData, customerFolders);

    return mySqlConnection.insertIpv6Subnets(ipv6Data);
  }).then(function () {
    console.log('Done');
  });
});