如何根据angularjs中的条件从控制器重定向页面？

Question

我一直在为每个 $http 请求和 url 更改进行身份验证。因此，我已经实现了 url 更改身份验证的代码和平，如下所示

/** login-controller.js file **/

//when the form is submitted
$scope.submit = function() {
    console.log("enter login submit");
    $scope.submitted = true;
    if (!$scope.loginForm.$invalid) {
        $scope.login($scope.credentials);
    } else {
        $scope.error = true;
        $scope.error_des = '';
        return;
    }
};

// if a session exists for current user (page was refreshed)
// log him in again
if ($window.sessionStorage["userInfo"]) {
        var credentials = JSON.parse($window.sessionStorage["userInfo"]);
        $scope.login(credentials);
};

//Performs the login function, by sending a request to the server with the Auth service
$scope.login = function(credentials) {

    $scope.error = false;
    Auth.login(credentials, function(user) {
        //success function
        $mdDialog.hide();
        $state.go("admin-panel.default.home");
    }, function(err) {
        console.log("error");
        $scope.error_des = err.msg;
        $scope.error = true;
    });
};

一切都按我的预期工作，但是在重新加载同一页面时，它总是会重定向到主页（http://localhost:3000/#/home).i 知道这是因为

$state.go("admin-panel.default.home");

麻烦的是，我想根据登录方式重定向页面假设如果用户通过提交的表单登录，它将被重定向到 $state.go("admin-panel.default.home"); 同样，如果当前用户存在通过会话登录的用户，则将被重定向到 $state.go("admin-panel.default."+$current_page);

如何实现呢？请帮帮我？？？

Answer 1

If form submit : var formsubmitted = true;
if login via session : formsubmitted = false
 and while routing you can check condition 
if(formsubmitted == true)
   $state.go("admin-panel.default.home");
else
$state.go("admin-panel.default."+$current_page);
//to get current page path  you can use $location.path();