【发布时间】:2017-06-12 15:39:09
【问题描述】:
在我的应用程序中,我有两个不同的表,它们通过第一个的 ID(一对多关系)相互关联。它应该首先以 JSON 格式从前端收集数据,如下所示:
cancellation = {
name: someting
id: someting
rule =
[
{someting}, {something}, {something}
]
}
一张用于取消,另一张用于规则。如果我想按此顺序排列这些信息,我需要先插入一条记录以进行取消。然后进行查询以找出该记录在数据库中的 ID 是什么,然后插入使用该 ID 作为外键的所有规则。但由于 Node JS 是异步的,因此在我获取有关记录程序星星的 ID 的信息以执行其余代码并将此变量视为未定义之前。
app.post('/databaseSend/cancellation', function(req,res){
var cancellationReceived = req.body;
var cancellationID;
var rules = [];
var cancellation = [];
cancellation[0] =
[
cancellationReceived.name,
cancellationReceived.id
]
// inserting data into cancellation table
connection.query("INSERT INTO cancellations (name, User_ID) VALUES ?", [cancellation],
function(err,results){
if(err){console.log(err)}
}
)
//fetching ID of the current record
connection.query("SELECT id FROM cancellations WHERE User_ID = ? AND name = ?", [cancellationReceived.id, cancellationReceived.name],
function(err, results){
var cancellationID = results[0].id;
});
//assigning ID to use it as a foreign key
for(var i = 0; i < cancellationReceived.rule.length; i++)
{
rules[i] =
[
cancellationReceived.rule[i].daysBefore,
cancellationReceived.rule[i].fee,
cancellationReceived.rule[i].type,
cancellationID
]
}
for(var i = 0; i < rules.length; i++)
{
console.log(rules[i]); // ID is undefined
}
});
我该如何解决这个问题?我尝试使用 setTimeout 来暂停我的代码,但它没有改变任何东西。
我用这个节点模块做mysql->https://github.com/mysqljs/mysql
【问题讨论】:
标签: mysql sql node.js database