【发布时间】:2014-09-13 18:36:41
【问题描述】:
下面给出了一个 Python 和 C++ 程序,它执行以下任务:从 stdin 读取空格分隔的单词,将按字符串长度排序的唯一单词以及每个唯一单词的计数打印到 stdout。输出的一行格式为:length、count、word。
例如,使用这个输入文件(488kB 的词库) http://pastebin.com/raw.php?i=NeUBQ22T
带有格式的输出是这样的:
1 57 "
1 1 n
1 1 )
1 3 *
1 18 ,
1 7 -
1 1 R
1 13 .
1 2 1
1 1 S
1 5 2
1 1 3
1 2 4
1 2 &
1 91 %
1 1 5
1 1 6
1 1 7
1 1 8
1 2 9
1 16 ;
1 2 =
1 5 A
1 1 C
1 5 e
1 3 E
1 1 G
1 11 I
1 1 L
1 4 N
1 681 a
1 2 y
1 1 P
2 1 67
2 1 y;
2 1 P-
2 85 no
2 9 ne
2 779 of
2 1 n;
...
这是C++程序
#include <vector>
#include <string>
#include <iostream>
#include <set>
#include <map>
bool compare_strlen (const std::string &lhs, const std::string &rhs) {
return (lhs.length() < rhs.length());
}
int main (int argc, char *argv[]) {
std::string str;
std::vector<std::string> words;
/* Extract words from the input file, splitting on whitespace */
while (std::cin >> str) {
words.push_back(str);
}
/* Extract unique words and count the number of occurances of each word */
std::set<std::string> unique_words;
std::map<std::string,int> word_count;
for (std::vector<std::string>::iterator it = words.begin();
it != words.end(); ++it) {
unique_words.insert(*it);
word_count[*it]++;
}
words.clear();
std::copy(unique_words.begin(), unique_words.end(),
std::back_inserter(words));
// Sort by word length
std::sort(words.begin(), words.end(), compare_strlen);
// Print words with length and number of occurances
for (std::vector<std::string>::iterator it = words.begin();
it != words.end(); ++it) {
std::cout << it->length() << " " << word_count[*it] << " " <<
*it << std::endl;
}
return 0;
}
这是 Python 程序:
import fileinput
from collections import defaultdict
words = set()
count = {}
for line in fileinput.input():
line_words = line.split()
for word in line_words:
if word not in words:
words.add(word)
count[word] = 1
else:
count[word] += 1
words = list(words)
words.sort(key=len)
for word in words:
print len(word), count[word], word
对于 C++ 程序,使用的编译器是带有 -O3 标志的 g++ 4.9.0。
使用的 Python 版本是 2.7.3
C++ 程序所用时间:
time ./main > measure-and-count.txt < ~/Documents/thesaurus/thesaurus.txt
real 0m0.687s
user 0m0.559s
sys 0m0.123s
Python 程序所用时间:
time python main.py > measure-and-count.txt < ~/Documents/thesaurus/thesaurus.txt
real 0m0.369s
user 0m0.308s
sys 0m0.029s
Python 程序比 C++ 程序快得多,并且在更大的输入大小下相对更快。这里发生了什么?我对 C++ STL 的使用不正确吗?
编辑:
根据评论和答案的建议,我将 C++ 程序更改为使用 std::unordered_set 和 std::unordered_map。
以下几行已更改
#include <unordered_set>
#include <unordered_map>
...
std::unordered_set<std::string> unique_words;
std::unordered_map<std::string,int> word_count;
编译命令:
g++-4.9 -std=c++11 -O3 -o main main.cpp
这只是略微提高了性能:
time ./main > measure-and-count.txt < ~/Documents/thesaurus/thesaurus.txt
real 0m0.604s
user 0m0.479s
sys 0m0.122s
Edit2:更快的 C++ 程序
这是 NetVipeC 的解决方案、Dieter Lücking 的解决方案和this question 的最佳答案的组合。真正的性能杀手是cin 默认使用无缓冲读取。已解决std::cin.sync_with_stdio(false);。此解决方案还使用单个容器,利用 C++ 中的有序 map。
#include <vector>
#include <string>
#include <iostream>
#include <set>
#include <map>
struct comparer_strlen {
bool operator()(const std::string& lhs, const std::string& rhs) const {
if (lhs.length() == rhs.length())
return lhs < rhs;
return lhs.length() < rhs.length();
}
};
int main(int argc, char* argv[]) {
std::cin.sync_with_stdio(false);
std::string str;
typedef std::map<std::string, int, comparer_strlen> word_count_t;
/* Extract words from the input file, splitting on whitespace */
/* Extract unique words and count the number of occurances of each word */
word_count_t word_count;
while (std::cin >> str) {
word_count[str]++;
}
// Print words with length and number of occurances
for (word_count_t::iterator it = word_count.begin();
it != word_count.end(); ++it) {
std::cout << it->first.length() << " " << it->second << " "
<< it->first << '\n';
}
return 0;
}
运行时
time ./main3 > measure-and-count.txt < ~/Documents/thesaurus/thesaurus.txt
real 0m0.106s
user 0m0.091s
sys 0m0.012s
Edit3: Daniel 提供了一个简洁明了的 Python 程序版本,它的运行时间与上述版本大致相同:
import fileinput
from collections import Counter
count = Counter(w for line in fileinput.input() for w in line.split())
for word in sorted(count, key=len):
print len(word), count[word], word
运行时:
time python main2.py > measure-and-count.txt.py < ~/Documents/thesaurus/thesaurus.txt
real 0m0.342s
user 0m0.312s
sys 0m0.027s
【问题讨论】:
-
std::mapvsstd::unordered_map? -
我没有足够的信心来欺骗这个,但这里可能是重复的:stackoverflow.com/questions/9371238/…
-
顺便说一句。使用 Python 是因为它的简短而不是速度:
count = Counter(l for line in fileinput.input() for l in line.split()) for word in sorted(count, key=len): print len(word), count[word], word -
尝试降低优化设置。拥有
-O3在某些情况下会降低 性能。尝试不同的优化设置。也可以尝试标记比较函数inline。 -
-O2 在我的机器上稍慢~(-10ms)
标签: python c++ performance io