Node.js 和 Socket.io 出错

Question

我正在按照此处提供的教程进行操作： http://www.davidado.com/2013/12/10/node-js-for-user-alert-push-notifications/ 目标是允许某人向另一个用户发送消息。

节点已安装并且可以工作。我还安装了 Socket.io。

当我跑步时

node server.js

我有这个错误：

TypeError: undefined is not a function
    at Socket.<anonymous> (/root/nodeapp/server.js:11:39)

server.js（服务器端）是这样的：

var io = require('socket.io').listen(5120);

io.sockets.on('connection', function (socket) {

   socket.on('join_room', function (data) {
      if (typeof socket !== 'undefined') {
         // data.id should be set if user is logged in
         if (typeof data.id !== 'undefined' && data.id > 0) {
            // Check if socket is already in room
            var roomlist = io.sockets.clients(data.id); // returns Socket instances of all clients in the room
            var occupantSocket;
            if (typeof roomlist[0] !== 'undefined') {
               // Should only be one socket in a private room
               occupantSocket = roomlist[0];
            }
            if (socket !== occupantSocket) {
               // Socket hasn't joined before so join it now
               socket.join(data.id);
            }
         } else {
            // User ID isn't set so disconnect the socket
            socket.disconnect();
         }
      }
   });

   socket.on('send_msg', function (data) {
      if (typeof socket !== 'undefined') {
         if (typeof data.id_sendee !== 'undefined' && data.id_sendee > 0) {
            // Check if anyone is in the room before broadcasting
            var roomlist = io.sockets.clients(data.id_sendee);
            if (typeof roomlist[0] !== 'undefined') {
               // Push alerts aren't that critical so use volatile
               socket.broadcast.to(data.id_sendee).volatile.emit(
                  'newalert',
                  {sender: data.sender, msg: data.msg });
            }
         } else {
            socket.disconnect();
         }
      }
   });
});
console.log("Hello , just checking!");

第 11 行是这一行：

var roomlist = io.sockets.clients(data.id); // 返回套接字 房间内所有客户的实例

在客户端，接收消息的一方：

<html>
    <head>
        <title>Test Node</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>


<script src="https://cdn.socket.io/socket.io-1.3.5.js"></script>
<script type="text/javascript">
var socket = io.connect('http://IPAdressofMyServer:5120');
socket.emit('join_room', { id: 234 });

// Listen for 'newalert' event from node server at server.js
socket.on('newalert', function (data) {
alert( data.msg + ' from ' + data.sender );
});
</script>
</head>
<body>
</body>
</html>

当我在控制台中启动 node server.js 时，没有错误，但只要我刷新客户端（使用上面的代码），就会触发错误。

知道问题是什么吗？ 谢谢你的帮助！

Answer 1

该功能在 1.0.x 版本中不可用。

请根据此链接更改您的代码：getting how many people are in a chat room in socket.io