查找，修改和删除递归嵌入文档猫鼬js答案

【问题标题】：Find, modificate and remove recursive embedded-document mongoosejs查找，修改和删除递归嵌入文档猫鼬js
【发布时间】：2012-10-08 05:15:00
【问题描述】：

我使用示例中的方案描述。

Comment.add({
    title     : { type: String, index: true }
  , date      : Date
  , body      : String
  , comments  : [Comment]
});

var BlogPost = new Schema({
    title     : { type: String, index: true }
  , slug      : { type: String, lowercase: true, trim: true }
  , date      : Date
  , buf       : Buffer
  , comments  : [Comment]
  , creator   : Schema.ObjectId
});

我在 cmets 中有几个级别的嵌套。如何在任何嵌套级别找到正确的评论并对其进行任何操作（删除编辑或添加新的嵌套评论）我尝试对搜索进行递归，但您无法保存或删除 cmets

BlogPost.methods.findComment = function (id, callback) {

  var curentComment = this.comments;
  var findComment = null;
  var recursiveFindComment = function(comment){
      for(i=0;i<comment.length;i++){
          if(findComment){
              break;
          }
          if(comment[i]._id == id){
              findComment  = comment[i];
              break;    
          }else if(comment[i].comments.length>0){
              findComment = recursiveFindComment(comment[i].comments)
          }
      }
      return findComment;

  }

  if(curentComment.id(id)){
     callback(curentComment);  
  }else{
     callback(recursiveFindComment(curentComment, null)) 
  }
}

【问题讨论】：

标签： node.js mongoose

【解决方案1】：

您可能想看看在 MongoDb (http://www.mongodb.org/display/DOCS/Trees+in+MongoDB) 中使用树。有许多不同的方法可以帮助您处理架构的递归性质。

> t = db.tree
test.tree

> // get entire tree -- we use sort() to make the order nice
> t.find().sort({path:1})
{ "_id" : "a", "path" : "a," }
{ "_id" : "b", "path" : "a,b," }
{ "_id" : "c", "path" : "a,b,c," }
{ "_id" : "d", "path" : "a,b,d," }
{ "_id" : "g", "path" : "a,b,g," }
{ "_id" : "e", "path" : "a,e," }
{ "_id" : "f", "path" : "a,e,f," }
{ "_id" : "g", "path" : "a,b,g," }

> t.ensureIndex( {path:1} )

> // find the node 'b' and all its descendents:
> t.find( { path : /^a,b,/ } )
{ "_id" : "b", "path" : "a,b," }
{ "_id" : "c", "path" : "a,b,c," }
{ "_id" : "d", "path" : "a,b,d," }
{ "_id" : "g", "path" : "a,b,g," }

> // find the node 'b' and its descendents, where path to 'b' is not already known:
> nodeb = t.findOne( { _id : "b" } )
{ "_id" : "b", "path" : "a,b," }
> t.find( { path : new RegExp("^" + nodeb.path) } )
{ "_id" : "b", "path" : "a,b," }
{ "_id" : "c", "path" : "a,b,c," }
{ "_id" : "d", "path" : "a,b,d," }
{ "_id" : "g", "path" : "a,b,g," }

【讨论】：