【发布时间】:2020-05-06 22:31:18
【问题描述】:
我有以下收藏:
{
id: 23423-dsfsdf-32423,
name: Proj1,
services: [
{
id:sdfs-24423-sdf,
name:P1_Service1,
products:[{},{},{}]
},
{
id:sdfs-24jhh-sdf,
name:P1_Service2,
products:[{},{},{}]
},
{
id:sdfs-2jnbn3-sdf,
name:P1_Service3,
products:[{},{},{}]
}
]
},
{
id: 23423-cxcvx-32423,
name: Proj2,
services: [
{
id:sdfs-xvxcv-sdf,
name:P2_Service1,
products:[{},{},{}]
},
{
id:sdfs-xvwqw-sdf,
name:P2_Service2,
products:[{},{},{}]
},
{
id:sdfs-erdfd-sdf,
name:P2_Service3,
products:[{},{},{}]
}
]
}
我需要返回一个包含所有服务数组的文档:
{
services: [
{
id:sdfs-24423-sdf,
name:P1_Service1,
products:[{},{},{}]
},
{
id:sdfs-24jhh-sdf,
name:P1_Service2,
products:[{},{},{}]
},
{
id:sdfs-2jnbn3-sdf,
name:P1_Service3,
products:[{},{},{}]
},
{
id:sdfs-xvxcv-sdf,
name:P2_Service1,
products:[{},{},{}]
},
{
id:sdfs-xvwqw-sdf,
name:P2_Service2,
products:[{},{},{}]
},
{
id:sdfs-erdfd-sdf,
name:P2_Service3,
products:[{},{},{}]
}
]
}
我得到的最多的是:
db.projects.aggregate({"$group":{"_id":"services","services":{"$push":"$services"}}})
但这会返回一个包含数组数组的文档,我想要一个对象数组:
{
_id:"services",
services:[
[
{
id:sdfs-24423-sdf,
name:P1_Service1,
products:[{},{},{}]
},
{
id:sdfs-24jhh-sdf,
name:P1_Service2,
products:[{},{},{}]
},
{
id:sdfs-2jnbn3-sdf,
name:P1_Service3,
products:[{},{},{}]
}
],
[
{
id:sdfs-xvxcv-sdf,
name:P2_Service1,
products:[{},{},{}]
},
{
id:sdfs-xvwqw-sdf,
name:P2_Service2,
products:[{},{},{}]
},
{
id:sdfs-erdfd-sdf,
name:P2_Service3,
products:[{},{},{}]
}
]
]
}
我无法弄清楚数组聚合或加入或联合或其他什么。 最终我也必须对产品做同样的事情(将所有项目的所有服务的所有产品作为一个产品数组并将文档返回到服务器,但首先要做的是......
10 倍
【问题讨论】:
标签: node.js mongodb mongodb-query