【发布时间】:2022-02-18 17:08:24
【问题描述】:
想在 Haskell 中实现类型安全的矩阵乘法。 定义如下:
{-# LANGUAGE TypeFamilies, DataKinds, GADTs #-}
module Vector where
data Nat = Succ Nat | Zero
data Vector (n :: Nat) a where
Nil :: Vector 'Zero a
(:::) :: a -> Vector n a -> Vector (Succ n) a
type Matrix n m a = Vector m (Vector n a)
instance Foldable (Vector n) where
foldr f b (a ::: as) = f a (foldr f b as)
foldr _ b Nil = b
instance Functor (Vector n) where
fmap f (x ::: xs) = f x ::: fmap f xs
fmap _ Nil = Nil
zipV :: (a -> b -> c) -> Vector n a -> Vector n b -> Vector n c
zipV f (a ::: as) (b ::: bs) = f a b ::: zipV f as bs
zipV f Nil Nil = Nil
终于有实现的需要
transpose :: Matrix n m a -> Matrix m n a
但我在 Haskell 中能做的最好的事情是:
transpose :: Matrix n (Succ m) a -> Matrix (Succ m) n a
transpose (h ::: rest@(_ ::: _)) = zipV (:::) h (transpose rest)
transpose (h ::: Nil) = fmap (::: Nil) h
因为我无法实现,所以限制为 m > 0
nils :: {n :: Nat} -> Vector n (Vector Zero a)
改用 Idris 只是为了练习并且做得更好:
matrix : Nat -> Nat -> Type -> Type
matrix n m a = Vector n (Vector m a)
nils : {n: Nat} -> Vector n (Vector Z a)
nils {n = Z} = Nil
nils {n = S k} = Nil ::: nils
transpose : matrix n m a -> matrix m n a
transpose (h ::: rest) = zipV (:::) h (transpose rest)
transpose Nil = nils
我有实现 nils 的冲动,但是 Haskell 中的类型级编程很尴尬。我还必须在 Haskell 中对 rest@(_ ::: _) 进行模式匹配,但我在 Idris 中没有。如何实现“nil”?
【问题讨论】:
-
我认为这是不可行的。在 Haskell 中,类型被擦除,因此从
Vector n t恢复n的唯一方法是模式匹配此类向量类型的某些值。当您只有Vector 0 (Vector n t)类型的值时,这是一个问题。解决此问题的一种方法是将singleton存储在矩阵类型中,例如Matrix n m a = (Sing n, Vector m (Vector n a))。否则,需要将单例作为transpose中的参数。
标签: haskell vector polymorphism dependent-type type-level-computation