如何修复此类型错误：无法读取 null 的属性“名称”

Question

如何解决这个错误

music.on('voiceStateUpdate',(lama, baru) => {
var state = null;  
let Role = baru.roles.find((r) => ["IRON", "BRONZE"].includes(r.name));
  const kategorikanal = '700743802574602260'
  const channelid = '700743824346972231'
  if(!lama.voiceChannel && !baru.voiceChannel) return;
  if(!lama.voiceChannel && baru.voiceChannel) {state = "join"}
  else if(lama.voiceChannel && !baru.voiceChannel) {state = "leave"}
  else if(lama.voiceChannel.id !== baru.voiceChannel.id) {state = "move"}
  else if(lama.voiceChannel.id == baru.voiceChannel.id) return;
  console.log(state);
//!baru.member.roles.has(allowedRole)
  if(baru.voiceChannelID === channelid || !baru.voiceChannelID === Role || Role !== null && Role !== '') {
console.log(baru.displayName + ' gabisabgo hrus ada rank ranked ');
   // const Role = baru.guild.roles.get("724997095236304987");
    baru.guild
    .createChannel(`${Role.name} | ${baru.user.username}`,"voice")
    .then(tempChannel => {
        tempChannel.overwritePermissions(baru.guild.defaultRole.id, {
   CONNECT: false,
})

    tempChannel.overwritePermissions(Role.id, {
        CONNECT: true
    })
      tempChannel.setParent(kategorikanal);
      baru.setVoiceChannel(tempChannel.id);
      tempChannel.setUserLimit("5");
      })
      
  .catch(console.error)
      
}
  if(lama.voiceChannelID || !lama.voiceChannelID === Role || Role !== null && Role !== '') {     
      console.log(lama.displayName + ' gabisabgo hrus ada rank ranked ');

      const voicelama = lama.guild.channels.get(lama.voiceChannelID);

    let Role = baru.roles.find((r) => ["IRON", "BRONZE"].includes(r.name));
      if(voicelama.name.startsWith(`${Role.name} | ${baru.user.username}`)){
      let sawadikap = `**${baru.user.username}'s**` + " **Team**"
      var koko = new Discord.RichEmbed()
      .setColor("#FF4654")
      .setThumbnail(`${baru.user.avatarURL}`)
      .addField('**Good Game Well Played**',`${sawadikap}`)
      .setFooter("@Valorant Indonesia Community." , 'https://i.imgur.com/yPWqxxu.png') 
       voicelama.delete()
      .then(function() {
        music.channels.get('725080861392896101').send(koko)
  })
      .catch(console.error);
  }
    }
  })

错误视图

.createChannel(${Role.name} | ${baru.user.username},"voice")
 ^  TypeError: Cannot read property 'name' of null 

Answer 1

您是否在调试模式下单步执行了代码？我建议您设置断点、创建监视程序并在您逐步执行时检查变量的值。如果您觉得这样做不舒服，您能否输入以下内容，并告诉我控制台记录的内容？ ：

console.log(Role)
console.log(Role.name)

虽然Role不是null，但Role.name的值是null，意味着它没有赋值。这个问题发生在这里：

let Role = baru.roles.find((r) => ["IRON", "BRONZE"].includes(r.name));

所以我看到了两种可能性：

1. 没有角色包含这些名称。
2. 我认为find 应该只产生一个结果，但我似乎找不到该方法的良好文档。是否有可能找到两个角色并返回一个集合？这意味着会有多个角色的集合，这意味着 Role 不会包含 Role 对象类型所包含的数据成员。这意味着您必须在使用名称之前为其中一个角色建立索引。

//

//if there isn't a matching role, then terminate the method.
if (Role == null)
{
    return;
}
//if there are multiple roles that match the criterion, just use the first one. 
//The alternative is that we could make it into a loop that handles it for all of them.
else if (Role instanceof Array)
{
    if (Role.length == 0)
    {
        return;
    }

    Role = Role[0]
}

在调用baru.guild.createChannel之前添加以上行。