如何递归检查文件包含依赖项的数组以获取其他依赖项？

Question

为了解释我的问题，让我首先指向这个数组：

<?php
$_depends = array(
    '/Scripting/jquery.hyponiqs/jquery.dropdown.js' => array(
        "/Scripting/jquery.externals/jquery.resize.js",
        "/Scripting/jquery.externals/jquery.topzindex.js",
        "/Scripting/jquery.externals/jquery.timers.js",
        "/Scripting/jquery-ui.min.js",
        "/Scripting/jquery.hyponiqs/hyponiqs.core.js",
    ),
    '/Script/UI/Dialogs.js' => array(
        "/Scripting/jquery.externals/jquery.resize.js",
        "/Scripting/jquery.externals/jquery.topzindex.js"
    ),
    '/Script/Display/List.js' => array(
        "/Scripting/jquery.externals/jquery.timers.js"
    )
);
?>

只要包含一个 JavaScript 文件，就会根据这个数组检查它的依赖关系。然后将每个文件的所有依赖项添加到最终的$includes 数组中。当我添加一个包含依赖项并且其中一个依赖项也有自己的依赖项时，问题就出现了，例如：

<?php
$_depends = array(
    '/Scripting/jquery.hyponiqs/jquery.dropdown.js' => array(
        "/Scripting/jquery.externals/jquery.resize.js",
        "/Scripting/jquery.externals/jquery.topzindex.js",
        "/Scripting/jquery.externals/jquery.timers.js",
        "/Scripting/jquery-ui.min.js",
        "/Scripting/jquery.hyponiqs/hyponiqs.core.js",
    ),
    '/Script/UI/Dialogs.js' => array(
        "/Scripting/jquery.externals/jquery.resize.js",
        "/Scripting/jquery.externals/jquery.topzindex.js"
    ),
    '/Script/Display/List.js' => array(
        "/Scripting/jquery.externals/jquery.timers.js"
    ),
    '/Script/UI/Calendar/Main.js' => array(
        "/Scripting/jquery-ui.min.js",
        "/Script/UI/Dialogs.js"
    )
);
?>

如您所见，添加的'/Script/UI/Calendar/Main.js' 依赖于"/Script/UI/Dialogs.js"，而"/Script/UI/Dialogs.js" 有自己的依赖关系。

我知道我必须递归检查依赖数组和最终包含数组，但我似乎无法理解逻辑。这里有一点帮助可能会很好。

更新

我将所有内容都封装在一个类中以说明其用途（尽管实际的类要复杂得多，并且具有各种其他包含处理功能：

<?php
class Script_Depends {
    private $_includes = array();

    private $_depends = array(
        '/Scripting/jquery.hyponiqs/jquery.dropdown.js' => array(
            "/Scripting/jquery.externals/jquery.resize.js",
            "/Scripting/jquery.externals/jquery.topzindex.js",
            "/Scripting/jquery.externals/jquery.timers.js",
            "/Scripting/jquery-ui.min.js",
            "/Scripting/jquery.hyponiqs/hyponiqs.core.js",
        ),
        '/Script/UI/Dialogs.js' => array(
            "/Scripting/jquery.externals/jquery.resize.js",
            "/Scripting/jquery.externals/jquery.topzindex.js"
        ),
        '/Script/Display/List.js' => array(
            "/Scripting/jquery.externals/jquery.timers.js"
        ),
        '/Script/UI/Calendar/Main.js' => array(
            "/Script/UI/Dialogs.js",
            "/Scripting/jquery-ui.min.js"
        )
    );

    public function includes($includes)
    {
        if (is_string($includes)) $includes = array($includes);

        foreach ($includes as $include) {
            if (isset($this->_depends[$include])) {
                $this->_includes = $this->includes($this->_depends[$include]);
                array_push($this->_includes, $include);
            }
            else {
                array_push($this->_includes, $include);
            }
        }

        $this->_includes = array_unique($this->_includes);

        return $this->_includes;
    }
}
?>

Answer 1

• 保留一个堆栈，最初是您的初始依赖项 (stack)
• 保留一个包含所有（传递）依赖项的空数组 (deps)
• 虽然堆栈不是empty
  • pop 最后一个元素 (el)
  • 将el 添加到deps
  • 循环遍历el的依赖
    • 如果依赖是indeps，什么都不做
    • 否则，push 将其转为stack

Answer 2

您要查找的函数称为 flatten。它采用递归列表并返回每个级别的所有元素。

这里的cmets中有一些php中的实现：http://php.net/manual/en/function.array-values.php

这里是 javascript 中的一个实现：http://tech.karbassi.com/2009/12/17/pure-javascript-flatten-array/

Answer 3

试试这个：

function getDependentFiles($file, $dependencies) {
    $fileIndex = array();
    $queue = array($file);
    while (count($queue)) {
        $f = array_shift($queue);
        if (!isset($fileIndex[$f])) {
            if (array_key_exists($f, $dependencies) && is_array($dependencies[$f])) {
                $queue = array_merge($queue, $dependencies[$f]);
            }
            $fileIndex[$f] = true;
        }
    }
    return array_keys($fileIndex);
}
var_dump(getDependentFiles('/Script/UI/Calendar/Main.js', $_depends));

这基本上实现了Artefacto描述的算法。

Answer 4

看看这是否能解决问题——你的功能的一个小模块。

（顺便说一句，由于您的命名约定，这令人费解：$includes、$include、$this->_includes 和 $this->includes()！建议您使用更好的名称。我已将该函数重命名为calculate_includes，但你也应该清理其他的。）

public function calculate_includes($includes) {

        foreach ((array)$includes as $include) {

            if(in_array($include, $this->_includes)) continue;

            if (isset($this->_depends[$include])) {
                $this->_includes = $this->calculate_includes($this->_depends[$include]);
            } else {
                array_push($this->_includes, $include);
            }
        }

        $this->_includes = array_unique($this->_includes);

        return $this->_includes;
    }