gitlab CI 构建脚本语法错误

Question

我正在尝试在 Gitlab CI 中运行构建脚本，但它抱怨我不理解的语法错误。

这是我在 Gitlab 中配置的脚本：

# test syntax of all *.php and *.ctp files
for f in $(find . -name "*.php" -or -name "*.ctp")
do 
    php -l $f
done

这是提交后 Gitlab 的输出：

cd /opt/gitlab-runner/embedded/service/gitlab-runner/tmp/builds/project-1 && git reset --hard && git clean -fdx && git remote set-url origin http://gitlab-ci-token:xxxxxx@git01.peoplefone.com/web/portals.git && git fetch origin
HEAD is now at da5f9b9 test CI 7
From http://git01.peoplefone.com/web/portals
   da5f9b9..559f74b  develop    -> origin/develop
cd /opt/gitlab-runner/embedded/service/gitlab-runner/tmp/builds/project-1 && git reset --hard && git checkout 559f74be65167b67cd7761cb8cbae8bcb528dd40
HEAD is now at da5f9b9 test CI 7
Previous HEAD position was da5f9b9... test CI 7
HEAD is now at 559f74b... test CI 8
# test syntax of all *.php and *.ctp files
for f in $(find . -name "*.php" -or -name "*.ctp")
/tmp/executor20150409-17218-twsoje: line 12: syntax error near unexpected token `echo'

如您所见，我的脚本中没有任何“回声”语句，有人可以帮助我吗？非常感谢。

Answer 1

在尝试了一下之后，下面的脚本工作了：

# test syntax of all *.php and *.ctp files
for file in $(find . -name *.php -or -name *.ctp); do
    php -l $file;
done

但我还是不明白上面的错误..