findall include 里面 include by use Sequelize答案

【问题标题】：findall include inside include by use Sequelizefindall include 里面 include by use Sequelize
【发布时间】：2021-01-09 09:22:19
【问题描述】：

我有 3 个表假期和 user_mangment 和用户

我想要找到所有假期，然后包含 user_mangment，然后通过 user_mangment 包含用户

这里是我所做的代码...模型之间的第一个关系

型号：

db.user_mangment.belongsTo(db.user, {
  foreignKey: "userId",
  as: "user",
});


db.vacation.belongsTo(db.user_mangment, {
  foreignKey: "userMangmentId",
  as: "user_mangment",
});

这里的代码findAll：

find_vacation:async(req,res)=>{
  var Sequelize = require('sequelize');
  await   vacation.findAll({
    include: ['user_mangment',{include:['user']}]

  }).then(data => {
    res.send(data)
  })

}

我得到了错误：

(node:548) UnhandledPromiseRejectionWarning: Error: Include unexpected. Element has to be either a Model, an Association or an object.

我不知道，也许我忘记了什么，所以请帮忙

【问题讨论】：

标签： node.js sequelize.js

【解决方案1】：

我解决了T_T

find_vacation:async(req,res)=>{
  var Sequelize = require('sequelize');
  await   vacation.findAll({
    include: [{model:user_mangment,as:'user_mangment',include:['user']}]

  }).then(data => {
    res.send(data)
  })

},

更好地使用这个代码是更多的细节

find_vacation:async(req,res)=>{
  var Sequelize = require('sequelize');
  await   vacation.findAll({
    include: [{model:user_mangment,as:'user_mangment',include:[{model:user,as:'user'}]}]

  }).then(data => {
    res.send(data)
  })

},

【讨论】：