【发布时间】:2015-12-23 12:16:58
【问题描述】:
我正在尝试为 GridView 编写一个简单的适配器,完全来自 GridView 的谷歌示例;这是我的 getView 函数。
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
imageView.setLayoutParams(new GridLayout.LayoutParams(120,120));
imageView.setScaleType(ImageView.ScaleType.CENTER);
imageView.setPadding(2, 2, 2, 2);
}
else
{
imageView = (ImageView) convertView;
}
imageView.setImageResource(mThumbIds[position]);
return imageView;
}
但是我在imageView.setLayoutParams(new GridLayout.LayoutParams(120,120));这一行遇到了一些这样的错误
Error:(39, 39) error: no suitable constructor found for LayoutParams(int,int)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParam (Context,AttributeSet) is not applicable
(actual argument int cannot be converted to Context by method invocation conversion)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParams(android.widget.GridLayout.LayoutParams) is not applicable
(actual and formal argument lists differ in length)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParams(MarginLayoutParams) is not applicable
(actual and formal argument lists differ in length)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParams(android.view.ViewGroup.LayoutParams) is not applicable
(actual and formal argument lists differ in length)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParams() is not applicable
(actual and formal argument lists differ in length)
constructor android.widget.GridLayout.LayoutParams.android.widget.GridLayout.LayoutParams(Spec,Spec) is not applicable
(actual argument int cannot be converted to Spec by method invocation conversion)
有什么解决办法吗?
【问题讨论】:
标签: android gridview layout layoutparams getview