WPF 滑块 VisualStateManager

Question

我正在尝试在 XAML 中创建自己的滑块样式，但我不太正确。 VisualState x:Name="Pressed" 没有被触发。

...
<ControlTemplate TargetType="Slider">
    <Grid>
        <VisualStateManager.VisualStateGroups>
            <VisualStateGroup Name="CommonStates">
                <VisualState Name="Normal" />
                <VisualState Name="MouseOver">
                    ...
                </VisualState>
                <VisualState Name="Pressed">
                    <Storyboard>
                        <ColorAnimation Storyboard.TargetName="RepeatButtonValueBrush" Storyboard.TargetProperty="Color" To="{StaticResource PressedValueColor}" Duration="0"/>
                        <ColorAnimation Storyboard.TargetName="RepeatButtonRestBrush" Storyboard.TargetProperty="Color" To="{StaticResource PressedTrackColor}" Duration="0"/>
                    </Storyboard>
                </VisualState>
                <VisualState Name="Disabled">
                    ...
            </VisualStateGroup>
        </VisualStateManager.VisualStateGroups>
        ...
    </Grid>
</ControlTemplate>
...

我做错了什么？

谢谢

Answer 1

您需要调用VisualStateManager.GoToState 方法来更改视觉状态。请参阅这篇VisualStateManager and Triggers 文章。