【发布时间】:2018-06-11 16:02:27
【问题描述】:
我开发了单击父节点以显示其子行。我只需要启用单击子数据应该将其子子行打开为递归行或表树。任何人都可以添加您的逻辑来帮助我理解并帮助其他人吗?
document.getElementById("products").addEventListener("click", function(e) {
if (e.target.tagName === "A") {
e.preventDefault();
var row = e.target.parentNode.parentNode;
while ((row = nextTr(row)) && !/\bparent\b/ .test(row.className))
toggle_it(row);
}
});
function nextTr(row) {
while ((row = row.nextSibling) && row.nodeType != 1);
return row;
}
function toggle_it(item){
if (/\bopen\b/.test(item.className))
item.className = item.className.replace(/\bopen\b/," ");
else
item.className += " open";
}
tbody tr {
display : none;
}
tr.parent {
display : table-row;
}
tr.open {
display : table-row;
}
<!--
Bootstrap docs: https://getbootstrap.com/docs
-->
<div class="container">
<table class="table" id="products">
<thead>
<tr>
<th>Product</th>
<th>Price</th>
<th>Destination</th>
<th>Updated on</th>
</tr>
</thead>
<tbody>
<tr class="parent">
<td><a href="#">+</a>Oranges</td>
<td>100</td>
<td>On Store</td>
<td>22/10</td>
</tr>
<tr>
<td>121</td>
<td>120</td>
<td>City 1</td>
<td>22/10</td>
</tr>
<tr>
<td>212</td>
<td>140</td>
<td>City 2</td>
<td>22/10</td>
</tr>
<tr>
<td>212</td>
<td>140</td>
<td>City 2</td>
<td>22/10</td>
</tr>
<tr class="parent">
<td><a href="#">+</a>Apples</td>
<td>100</td>
<td>On Store</td>
<td>22/10</td>
</tr>
<tr>
<td>120</td>
<td>120</td>
<td>City 1</td>
<td>22/10</td>
</tr>
<tr>
<td>120</td>
<td>140</td>
<td>City 2</td>
<td>22/10</td>
</tr>
</tbody>
</table>
</div>
【问题讨论】:
标签: javascript html