如何成功地将我的 .h 文件实施到我的主 .cpp 文件中以使其正常运行

Question

代码应该从 .h 文件中获取类，并在主文件中使用它来创建自定义宠物概要，稍后可以将其存储在另一个文本文件中。我还没有对文本文件进行模块化提取，因为我至少需要让它工作并且能够实际编译和返回构成自定义宠物概要的不同数组。

/usr/bin/ld: /tmp/: in function `__static_initialization_and_destruction_0(int, int)':
program3.cpp:(.text+0x411): undefined reference to `dog_list::dog_list()'
/usr/bin/ld: program3.cpp:(.text+0x426): undefined reference to `dog_list::~dog_list()'
collect2: error: ld returned 1 exit status

我的 .h 文件

#include<iostream>
#include<cstring>
#include<cctype>
#include<fstream>
using namespace std;
const int SIZE = 20;
const int END = 11;
class dog_list
{
    public:
    dog_list();
    ~dog_list();
    void record_pets();
    private:
    char name[SIZE];
    char breed[SIZE];
    char species[SIZE];
    char service[SIZE];
    char special[SIZE];
};
dog_list op;


void record_pets();

---

我的主 .cpp 文件

#include "program3.h"
int main()
{
       op.record_pets();
        return 0;

}


void dog_list::record_pets()
{
    char personal_list[SIZE];
    int i = 0;
    char again;

    do
    {

        cout << "Enter in pets name: ";
        cin.get(op.name,25,'\n');
        cin.ignore(100,'\n');   
        cout << endl << "Enter breed of pet:  ";
        cin.get(op.breed, 25, '\n');
        cin.ignore(100,'\n');
        cout << endl << "Enter species: ";
        cin.get(op.species,25,'\n');
        cin.ignore(100,'\n');
        cout << endl <<  "Enter in service qualifications: ";
        cin.get(op.service,25,'\n');
        cin.ignore(100,'\n');
        cout << endl << "Enter in special notes: ";
        cin.get(op.special,25,'\n');
        cin.ignore(100,'\n');
        cout << endl;

        cout << "Name:  " << op.name << endl;
        cout <<"Breed: " <<  op.breed << endl;
        cout << "Species: " << op.species << endl;
        cout << "Service Qualifications: " << op.service << endl;
        cout << "Special Notes: " << op.special << endl;

        cout << "Pet saved! Would you like to enter another pet? Y/N: " << endl;
        cin >> again;
        cin.ignore(100,'\n');
        cout << endl;

        if(again == 'y')
        {
            again = toupper(again);
        }


    }while(again == 'Y' && i <= END);
    {
        ++i;    
    }   
}

Answer 1

你永远不会实现构造函数和析构函数，你只是声明它：

dog_list();
~dog_list();

你必须实现它，例如，在 main.cpp 中：

dog_list::dog_list() = default;
dog_list::~dog_list() = default;