org.openqa.selenium.support.ui.UnexpectedTagNameException：元素应该是“选择”但是“标题”

Question

我的应用程序有一个下拉菜单，其中显示了批处理运行的时间 <span class="select2-selection__rendered" id="select2-siTime-container" title="10 AM - 11 AM">10 AM - 11 AM</span> 单击下拉列表旁边的下拉列表后，我将获得要选择的值。

<ul class="select2-results__options ps-container ps-theme-default ps-active-y" role="tree" id="select2-siTime-results" aria-expanded="true" aria-hidden="false" data-ps-id="e0656a98-863d-cab8-ceca-763253acd3a0">
  <li class="select2-results__option" id="select2-siTime-result-sl6p-TIME_6" role="treeitem" aria-selected="false">6 AM - 7 AM</li>
  <li class="select2-results__option" id="select2-siTime-result-ogb9-TIME_7" role="treeitem" aria-selected="false">7 AM - 8 AM</li>
  <li class="select2-results__option" id="select2-siTime-result-wx7b-TIME_8" role="treeitem" aria-selected="false">8 AM - 9 AM</li>

当我尝试选择下拉菜单时，我看到了错误

元素应该被选中，但标题是

我的代码：

Select mycombo = new Select(driver.findElement(By.tagName("title")));
driver.findElement(By.xpath("//*[@aria-labelledby='select2-siTime-container']/span[2]")).click();
Thread.sleep(8000);
mycombo.selectByIndex(4);

Answer 1

Select 类只能用于<select> 标签。要从此下拉列表中选择一个选项，请单击它，然后单击该选项。类似的东西

WebElement dropdown = driver.findElement(By.id("select2-siTime-results"));
dropdown.click();
List<WebElement> options = dropdown.findElements(By.className("select2-results__option"));
options.get(4).click();