【发布时间】:2017-08-28 16:38:42
【问题描述】:
我想这样做:我有一个列表,其中每两个项目的颜色都不同,并且想要选择被点击的项目。选中的项目高亮显示,但释放后返回旧颜色
我这样做了: Artist_list_background_alternate.xml:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:state_selected="false"
android:state_pressed="false"
android:drawable="@color/sign_out_color" />
<item android:state_pressed="true"
android:drawable="@color/survey_toplist_item" />
<item android:state_selected="true"
android:state_pressed="false"
android:drawable="@color/survey_toplist_item" />
</selector>
artists_list_backgroundcolor.xml:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="@color/grey" android:state_pressed="false" android:state_selected="false" />
<item android:drawable="@color/survey_toplist_item" android:state_pressed="true" />
<item android:drawable="@color/survey_toplist_item" android:state_pressed="false" android:state_selected="true" />
<item android:drawable="@color/survey_toplist_item" android:state_pressed="false" android:state_selected="true" />
</selector>
Java 文件代码::
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View view = convertView;
if (view == null) {
view = lInflater.inflate(R.layout.listitem, parent, false);
}
if (position % 2 == 0) {
view.setBackgroundResource(R.drawable.artists_list_backgroundcolor);
} else {
view.setBackgroundResource(R.drawable.artists_list_background_alternate);
}
((TextView) view.findViewById(R.id.heading)).setText(data.get(position));
return view;
}
ListView lvMain = (ListView) findViewById(R.id.list);
lvMain.setAdapter(adapter);
布局xml ::
<ListView
android:id="@+id/list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:cacheColorHint="#00000000"
android:dividerHeight="1dp" />
我不知道我做错了什么
【问题讨论】: