如何在 youtube 搜索列表中应用分页..？答案

【问题标题】：How to apply pagination in youtube search list..?如何在 youtube 搜索列表中应用分页..？
【发布时间】：2015-04-26 14:18:29
【问题描述】：

我正在开发 youtube api，我想应用分页但我不知道该怎么做我在谷歌上搜索，只得到我必须得到页面令牌的信息但我不知道如何获取页面令牌请帮我解决这个问题谢谢。

    <?php

$htmlBody = <<<END
<form method="GET">
  <div>
    Search Term: <input type="search" id="q" name="q" placeholder="Enter Search Term">
  </div>
  <div>
    Max Results: <input type="number" id="maxResults" name="maxResults" min="1" max="50" step="1" value="25">
  </div>
  <input type="submit" value="Search">

</form>
END;

// This code will execute if the user entered a search query in the form
// and submitted the form. Otherwise, the page displays the form above.
if ($_GET['q'] && $_GET['maxResults']) {
  // Call set_include_path() as needed to point to your client library.
  require_once ($_SERVER["DOCUMENT_ROOT"].'/youtube/google-api-php-client/src/Google_Client.php');
  require_once ($_SERVER["DOCUMENT_ROOT"].'/youtube/google-api-php-client/src/contrib/Google_YouTubeService.php');

  /*
   * Set $DEVELOPER_KEY to the "API key" value from the "Access" tab of the
   * Google Developers Console <https://console.developers.google.com/>
   * Please ensure that you have enabled the YouTube Data API for your project.
   */
  $DEVELOPER_KEY = 'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX';

  $client = new Google_Client();
  $client->setDeveloperKey($DEVELOPER_KEY);

  // Define an object that will be used to make all API requests.
  $youtube = new Google_YoutubeService($client);

  try {
    // Call the search.list method to retrieve results matching the specified
    // query term.
    $searchResponse = $youtube->search->listSearch('id,snippet', array(
      'q' => $_GET['q'],
      'maxResults' => '10',
    ));

    $videos = '';
    $channels = '';
    $playlists = '';

    // Add each result to the appropriate list, and then display the lists of
    // matching videos, channels, and playlists.
    foreach ($searchResponse['items'] as $searchResult) {
      switch ($searchResult['id']['kind']) {
        case 'youtube#video':
          $videos .= sprintf('<a href=new/yt.php?videoid='.$searchResult['id']['videoId'].' target=_blank><li>%s (%s)</li>', $searchResult['snippet']['title'],
            $searchResult['id']['videoId']."   Watch This Video<br><img  src=' http://img.ytapi.com/vi/".$searchResult['id']['videoId']."/mqdefault.jpg' /></a>");
          break;
        case 'youtube#channel':
          $channels .= sprintf('<li>%s (%s)</li>',
              $searchResult['snippet']['title'], $searchResult['id']['channelId']);
          break;
        case 'youtube#playlist':
          $playlists .= sprintf('<li>%s (%s)</li>',
              $searchResult['snippet']['title'], $searchResult['id']['playlistId']);
          break;
      }
    }

    $htmlBody .= <<<END
    <h3>Videos</h3>
    <ul>$videos</ul>
    <h3>Channels</h3>
    <ul>$channels</ul>
    <h3>Playlists</h3>
    <ul>$playlists</ul>
END;
  } catch (Google_ServiceException $e) {
    $htmlBody .= sprintf('<p>A service error occurred: <code>%s</code></p>',
      htmlspecialchars($e->getMessage()));
  } catch (Google_Exception $e) {
    $htmlBody .= sprintf('<p>An client error occurred: <code>%s</code></p>',
      htmlspecialchars($e->getMessage()));
  }
  ?>
      <h1><a href="<?php echo $_SERVER['REQUEST_URI'] ?>/<?php echo $searchResponse['nextPageToken'] ?>">next</a></h1>

<?php
}
?>

<!doctype html>
<html>
  <head>
    <title>YouTube Search</title>
  </head>
  <body>
    <?=$htmlBody?>
  </body>
</html>

【问题讨论】：

标签： youtube pagination youtube-api

【解决方案1】：

搜索响应将返回一个“nextPageToken”，可能还有一个“prevPageToken”，它可以与您的下一个请求一起传递（除了更改页面令牌，它应该与当前请求相同）以获得一组不同的数据。您使用“pageToken”参数传递它（不像您的代码在此处作为 URL 路径的一部分）。因此，例如，您可以将搜索请求修改为如下所示：

$searchResponse = $youtube->search->listSearch('id,snippet', array(
  'q' => $_GET['q'],
  'maxResults' => '10',
  'pageToken' => $_GET['pageToken']
));

然后，显示您的搜索结果，并在其下方修改“下一个”链接，如下所示：

<h1><a href="<?php echo $_SERVER['REQUEST_URI'] ?>?q=<?php echo $_GET['q']>&pageToken=<?php echo $searchResponse['nextPageToken'] ?>">next</a></h1>

【讨论】：