文本对齐 R

Question

我想复制此演示文稿：

这是我的代码，但我得到了左侧对齐的列文本。您知道如何将其向右对齐吗？

cat("===========================================================\n \n") 
cat("\n Statistiques des variables vitesse_10km vitesse_21km \n") 
cat("----------------------------------------------------------- \n \n") 
cat("\t ", "\t ", "vitesse_10km", "\t ", "vitesse_21km", "\n")
cat("Moyenne   ", "\t ", mean10,  "\t ", "\t ", mean21, "\n")
cat("Ecart-type   ", "\t ", sd10, "\t ","\t ", sd21, "\n")
cat("Minimum  ", "\t ", min10, "\t ", "\t ", min21, "\n")
cat("Maximum  ", "\t ", max10, "\t ", max21, "\n")
cat("===========================================================\n \n")

Answer 1

您可以使用 sprintf 来格式化固定大小的数字（或字符串），并用前导空格填充。示例：

> cat(sprintf("++% 8.2f++", 20))
++   20.00++