【发布时间】:2018-04-25 12:13:25
【问题描述】:
我有两个简单的文件:leads.html 和 leadsController.js。我想将leadsController.js 作为leads.html 中的链接javascript 文件。当我在leads.html 中使用以下代码<script src = "leadsController.js"></script> 链接它时... leads.html 无法正确呈现。
但是,当我将leadsController.js 的内容作为leads.html 代码的一部分包含在内时,它可以工作。
我没有正确链接 .js 文件吗?
以下是有效的和无效的。
我希望它在连接到 leadsController.js 时能够正常工作
是的......它在同一个目录中。
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<meta http-equiv="x-ua-compatible" content="ie=edge">
<title></title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.9/angular.min.js"></script>
</head>
<body>
<div ng-app = "myApp" ng-controller = "myCtrl">
<h1>Hello, world!</h1>
<ul>
<li ng-repeat = "x in myData">{{ x.id }}</li>
</ul>
</div>
<script src = "leadsController.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.2/js/bootstrap.min.js" integrity="sha384-vZ2WRJMwsjRMW/8U7i6PWi6AlO1L79snBrmgiDpgIWJ82z8eA5lenwvxbMV1PAh7" crossorigin="anonymous"></script>
</body>
</html>
leadsController.js 看起来像这样:
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $http) {
$http.get("https://clearmaze.net/test/newAdmin/leadsData.php").then(function (response) {
$scope.myData = response.data.records;
});
});
这行得通:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<meta http-equiv="x-ua-compatible" content="ie=edge">
<title></title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.9/angular.min.js"></script>
</head>
<body>
<div ng-app = "myApp" ng-controller = "myCtrl">
<h1>Hello, world!</h1>
<ul>
<li ng-repeat = "x in myData">{{ x.id }}</li>
</ul>
</div>
<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $http) {
$http.get("leadsData.php").then(function (response) {
$scope.myData = response.data.records;
});
});
</script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.2/js/bootstrap.min.js" integrity="sha384-vZ2WRJMwsjRMW/8U7i6PWi6AlO1L79snBrmgiDpgIWJ82z8eA5lenwvxbMV1PAh7" crossorigin="anonymous"></script>
</body>
</html>
【问题讨论】:
-
你应该在
leadsController.js之前移动angular.min -
@TanDuong 感谢您的回复...
angular.min已经在leadsController.js之前。根据您的建议,我确实尝试过移动它但没有运气。 -
<script src = "./leadsController.js"></script>怎么样 -
不...没用:'(
标签: javascript html angularjs src